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Amiraneli [1.4K]
3 years ago
8

The domain is the set of all values a function will accept as _____.

Mathematics
1 answer:
Marina86 [1]3 years ago
8 0

Answer:

  ... inputs.

Step-by-step explanation:

A function is a map of inputs to outputs. The domain of a function is the set of <em>inputs</em> for which outputs are defined.

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The setAconsists of nine positive integers, none of which has a prime divisor larger thansix. Prove thatAis guaranteed to contai
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3 years ago
a vial of medicine contains 76 fluid ounces of medicine. If one dose consists of 2 fluid ounces how many doses does the vial con
Fudgin [204]
Then it contains 38 doses becasue 76 divide 2 is 38

7 0
3 years ago
How would the expression x^3-3sqrt(3) be rewritten using difference of cubes?
Semenov [28]
The difference of two cubes is factored by
x^3-y^3=(x-y)(x^2+xy+y^2)

In this case it would be

C) 
3 0
3 years ago
Read 2 more answers
Circle O, with center (x, y), passes through the points A(0, 0), B(–3, 0), and C(1, 2). Find the coordinates of the center of th
balandron [24]
The answer:

the main formula of the circle's equation is 
(x-a)²+ (y-b)² = R²
where C(a, b) is the center of the circle
R is the radius

if a point A(x', y') passes through the circle, so the equation of the circle can be written as 
(x'-a)²+ (y'-b)² = R², and that is  a main formula.


<span>Circle O, with center (x, y), passes through the points A(0, 0), B(–3, 0), and C(1, 2), so we have exactly three equation:
</span>
(0-x)² + (0-y)² = R², circle O passes through A
x²+y²= R²
(-3 -x)² + (0-y)² = R², circle O passes through B
(-3 -x)² + (y)² = R²
(1-x)² + (2-y)² = R², circle O passes through A
(1-x)² + (2-y)² = R²

and we know that R= OA = OC= OB, 
OA=R= sqrt( (0-x)² + (0-y)² ) = OB = sqrt((-3 -x)² + (0-y)²), this implies

x²+y² = (-3 -x)² + (0-y)² , it implies x² = 9+ x² + 6x , and then -9/6=x, x= -3/2
and when OA = OC
x²+y² =(1-x)² + (2-y)²  so, x²+y² =1+x²-2x +4+y²-4y, therefore -5= -2x -4y
 -5= -2x -4y, when x = -3 /2   we obtain y = 2

the center is C(-3/2, 2)
7 0
4 years ago
Solve for x. whats the solutions from least to greatest. 4x^2 + 48x + 128 = 0
Anastasy [175]

Answer:

\boxed{\sf \ \ \ x = -8 \ or \ x = -4 \ \ \ }

Step-by-step explanation:

Hello,

4x^2+48x+128=0\\ 4(x^2+12x+32)=0\\ x^2+12x+32=0\\ (x+6)^2 - 36 + 32= 0\\\\ (x+6)^2-4=0\\ (x+6+2)(x+6-2)=0\\ (x+8)(x+4) = 0\\ x = -8 \ or \ x = -4

5 0
4 years ago
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