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serious [3.7K]
2 years ago
10

You pick a card at random. Without putting the first card back, you pick a second card at random.

Mathematics
1 answer:
Sladkaya [172]2 years ago
8 0

Answer:

1/6 or 16

Step-by-step explanation:

I hope this is the correct answer

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yes

Step-by-step explanation:

I think sorry if I am wrong

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Answer:

your answer will be <em><u>B. HL Theorem </u></em>

Step-by-step explanation:

hope it helps you...

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3 years ago
1. You are conducting a survey of the people in the United States to find out how popular racket sports (tennis, badminton, racq
andrey2020 [161]

Answer:

i think it's d

Step-by-step explanation:

4 0
4 years ago
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The vertex of this parabola is at (2,-1) when the y value is 0 and then x value is 5 what is the coefficient of the squared term
Darina [25.2K]

\bf ~~~~~~\textit{parabola vertex form} \\\\ \begin{array}{llll} \stackrel{\textit{we'll use this one}}{y=a(x- h)^2+ k}\\\\ x=a(y- k)^2+ h \end{array} \qquad\qquad vertex~~(\stackrel{2}{ h},\stackrel{-1}{ k}) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{cases} h=2\\ k=-1 \end{cases}\implies y=a(x-2)^2-1 \\\\\\ \textit{we also know that } \begin{cases} y=0\\ x=5 \end{cases}\implies 0=a(5-2)^2-1\implies 1=9a \\\\\\ \cfrac{1}{9}=a\qquad therefore\qquad \boxed{y=\cfrac{1}{9}(x-2)^2-1}


now, let's expand the squared term to get the standard form of the quadratic.


\bf y=\cfrac{1}{9}(x-2)^2-1\implies y=\cfrac{1}{9}(x^2-4x+4)-1 \\\\\\ y=\cfrac{1}{9}x^2-\cfrac{4}{9}x+\cfrac{4}{9}-1\implies \stackrel{its~coefficient}{y=\stackrel{\downarrow }{\cfrac{1}{9}}x^2-\cfrac{4}{9}x-\cfrac{5}{9}}

4 0
3 years ago
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PLZZZZ HELP! BRAINLIEST :)
alisha [4.7K]

Answer: An exponential function

Step-by-step explanation:

The data curves upward, slowly becoming closer and closer to a vertical line.

Hope it helps <3

5 0
3 years ago
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