All categories

1 year ago

I am a trinomial whose leading coefficient is -3 when I'm put in standard form:

Mathematics

1 answer:

Nikolay [14]1 year ago

7 0

Answer:

C. 4x² - 3x⁴ + x

General Formulas and Concepts:

Algebra I

Terms/Coefficients
Standard Form: Largest degree to smallest degree
Leading Coefficient: Constant multiplied to largest degree

Step-by-step explanation:

Step 1: Define

A. 2xy - 3 + 5xy²

B. 3x³ - 3x - 3

C. 4x² - 3x⁴ + x

D. x⁵y - 3x²y - xy

Step 2: Rewrite

Rewrite each trinomials into standard form.

A. 5xy² + 2xy - 3

B. 3x³ - 3x - 3

C. -3x⁴ + 4x² + x

D. x⁵y - 3x²y - xy

Step 3: Identify LC

A. has a leading coefficient of 5

B. has a leading coefficient of 3

C. has a leading coefficient of -3 (our answer)

D. has a leading coefficient of 1

You might be interested in

An elevator weighing 15,000 newtons is raised one story in 50 seconds. If the distance between stories is 3.0 meters, how much p

Dennis_Churaev [7]

Answer:

900 W

Step-by-step explanation:

4 0

2 years ago

Is the distance between -7 and -13 on a number line 6?

sattari [20]

Answer:

yes

Step-by-step explanation:

13-7=6 so that's the difference

4 0

2 years ago

8y-10=6y-2 help me please I don't get this

murzikaleks [220]

6 0

2 years ago

Read 2 more answers

A tennis tournament has 2n contestants. We want to pair them up for the first round of singles matches. Show that the number of

ddd [48]

There are

$\dbinom{2n}2 = \dfrac{(2n)!}{2! (2n-2)!}$

ways of pairing up any 2 members from the pool of $2n$ contestants. Note that

$(2n)! = 1\times2\times3\times4\times\cdots\times(2n-2)\times(2n-1)\times(2n) = (2n-2)! \times(2n-1) \times(2n)$

so that

$\dbinom{2n}2 = \dfrac{(2n)\times(2n-1)\times(2n-2)!}{2! (2n-2)!} = \boxed{n(2n-1)}$

4 0

1 year ago

What is the distance around this figure?

prisoha [69]

Answer:

Step-by-step explanation:

i think? i may have not understood the picture correctly, so if this is wrong i apologise

3 0

2 years ago