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Liula [17]
2 years ago
9

I am a trinomial whose leading coefficient is -3 when I'm put in standard form:

Mathematics
1 answer:
Nikolay [14]2 years ago
7 0

Answer:

C. 4x² - 3x⁴ + x

General Formulas and Concepts:

<u>Algebra I</u>

  • Terms/Coefficients
  • Standard Form: Largest degree to smallest degree
  • Leading Coefficient: Constant multiplied to largest degree

Step-by-step explanation:

<u>Step 1: Define</u>

A. 2xy - 3 + 5xy²

B. 3x³ - 3x - 3

C. 4x² - 3x⁴ + x

D. x⁵y - 3x²y - xy

<u>Step 2: Rewrite</u>

<em>Rewrite each trinomials into standard form.</em>

A. 5xy² + 2xy - 3

B. 3x³ - 3x - 3

C. -3x⁴ + 4x² + x

D. x⁵y - 3x²y - xy

<u>Step 3: Identify LC</u>

A. has a leading coefficient of 5

B. has a leading coefficient of 3

C. has a leading coefficient of -3 (our answer)

D. has a leading coefficient of 1

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2 years ago
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Step-by-step explanation:

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2(b+3c) equivalent expressions<br>Options: <br><br>3(b+2c)<br>(b+3c) +(b+3c)<br>None of the above
Lana71 [14]
2(b + 3c) → We first need to simplify this.

Simplify.

2b + 6c

1st Option : 

3(b + 2c)

Simplify.

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2nd Option :

(b + 3c) + (b + 3c)

Simplify.

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This is CORRECT because 2b+6c = 2b+6c

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5 0
3 years ago
The difference between the square of two numbers is 11. Twice the square of the first number increased by the square of the seco
jeyben [28]

Answer:

Below in bold.

Step-by-step explanation:

x^2 - y^2 = 11

2x^2  + y^2 = 97

From the first equation:

y^2 = x^2 - 11

Substituting in the second equation:

2x^2 + x^2 - 11 = 97

3x^2 = 108

x^2 = 36

x = 6, -6.

Substituting  for x in the first equation:

(6)^2 - y^2 = 11

y^2 = 36 - 11 = 25

y = 5, -5.

6 0
3 years ago
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chubhunter [2.5K]

Answer:

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Step-by-step explanation:

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