1..... 8(x+6)=-64
8x+48 =-64
8x =-64-48
8x=-112
X=-112/8
x=-14....
2.....3(4-2y)=-15
12-6y=-15
-6y=-15-12
-6y = - 27
y=27/6
y=4½....
3.....8w-3w+6=41
5w=41-6
5w=35
W=35/5
w=7....
4.....9x+3+x=-77
10x=-77-3
10x=-80
x=-8...
5.....10(-x-2)=120
-10x-20=120
-10x=120+20
-10x=140
x=140/-10
x=-14...
You shouldn't have a problem with the rest now....
Answer:
a) The sensor will read 75 liters at 5 minutes
Step-by-step explanation:
a) set up as a proportion and cross multiply to solve.
15 liters/1 minute = x/5 minutes
x = 75 liters
(negative infinity, 2] [2,infinity)
Step-by-step explanation:
well, as you can witness both of the equations are equal to y, so you're free to reckon that they are equal as well

Answer:
System has equal number of unknowns and equations.
Manipulation easily yielded expressions for 4 of the 7 unknowns.
However it seems that the remaining 3 unknowns x,y,z are not fixed by the equations. Different combinations (x0,y0,z0) seem possible without violating the system equations.
Is this possible, or did I most probably make a mistake in counting degrees of freedom?
Step-by-step explanation: