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Georgia [21]
3 years ago
6

Khalid is reading a 438-page book. He read for 3.5 hours on both Saturday and Sunday. On Saturday, he read 38 pages per hour. On

Sunday, he read 44 pages per hour. How many more pages must he read to finish the book?Immersive Reader
Mathematics
2 answers:
emmainna [20.7K]3 years ago
3 0

Answer:

He has 151 pages left in his book

Step-by-step explanation:

Saturday

1 hr = 38 pg

3.5 x 38 = 133

Sunday

1 hr = 44 pg

3.5 x 44 = 154

pages read

133 + 154 = 287

starting amount 438

438 - 287 = 151

Natasha2012 [34]3 years ago
3 0

Answer:

Step-by-step explanation:

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VashaNatasha [74]

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maksim [4K]

Answer:

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Step-by-step explanation:

6 0
3 years ago
Solve the system by substitution​
Alexxandr [17]
1) Solve one of the equations for either variable.

2) Substitute the expression from Step 1 into the other equation.

3) Solve the resulting equation.

4) Substitute the solution in Step 3 into one of the original equations to find the other variable.

5) Write the solution as an ordered pair.
5 0
2 years ago
The sum of twice a first number and five times a second number is 78. If the second number is subtracted from five times the fir
ss7ja [257]
The numbers are:  "9" and "12" .
___________________________________
Explanation:
___________________________________
Let:  "x" be the "first number" ; AND:

Let:  "y" be the "second number" .
___________________________________
From the question/problem, we are given:
___________________________________
     2x + 5y = 78 ;  → "the first equation" ; AND:

     5x − y = 33 ;  → "the second equation" .
____________________________________
From "the second equation" ; which is:

   " 5x − y = 33" ; 

→ Add "y" to EACH side of the equation; 

              5x − y + y = 33 + y ;

to get:  5x = 33 + y ; 

Now, subtract: "33" from each side of the equation; to isolate "y" on one side of the equation ; and to solve for "y" (in term of "x");

            5x − 33 = 33 + y − 33 ;

to get:   " 5x − 33 = y " ;  ↔  " y = 5x − 33 " .
_____________________________________________
Note:  We choose "the second equation"; because "the second equation"; that is;  "5x − y = 33" ;  already has a "y" value with no "coefficient" ; & it is easier to solve for one of our numbers (variables); that is, "x" or "y"; in terms of the other one; & then substitute that value into "the first equation".
____________________________________________________
Now, let us take "the first equation" ; which is:
  "  2x + 5y = 78 " ;
_______________________________________
We have our obtained value; " y = 5x − 33 " .
_______________________________________
We shall take our obtained value for "y" ; which is: "(5x− 33") ; and plug this value into the "y" value in the "first equation"; and solve for "x" ;
________________________________________________
Take the "first equation":
 ________________________________________________
      →   " 2x + 5y = 78 " ;  and write as:
________________________________________________ 
      →   " 2x + 5(5x − 33) = 78 " ;
________________________________________________
Note the "distributive property of multiplication" :
________________________________________________
     a(b + c) = ab + ac ; AND:

     a(b − c) = ab − ac .
________________________________________________
So; using the "distributive property of multiplication:

→   +5(5x − 33)  = (5*5x) − (5*33) =  +25x − 165 .
___________________________________________________
So we can rewrite our equation:

          →  " 2x + 5(5x − 33) = 78 " ;

by substituting the:  "+ 5(5x − 33) " ;  with:  "+25x − 165" ; as follows:
_____________________________________________________

          →  " 2x + 25x − 165 = 78 " ;
_____________________________________________________
→ Now, combine the "like terms" on the "left-hand side" of the equation:

              +2x + 25x = +27x ; 

Note:  There are no "like terms" on the "right-hand side" of the equation.
_____________________________________________________
    →  Rewrite the equation as:
_____________________________________________________
         →   " 27x − 165 = 78 " ;

      Now, add "165" to EACH SIDE of the equation; as follows:

         →    27x − 165 + 165 = 78 + 165 ;

        →  to get:      27x = 243  ;
_____________________________________________________
      Now, divide EACH SIDE of the equation by "27" ; to isolate "x" on one side of the equation ; and to solve for "x" ;
_____________________________________________________
               27x / 27  =  243 / 27 ; 

       →   to get:    x = 9 ; which is "the first number" .
_____________________________________________________
Now;    Let's go back to our "first equation" and "second equation" to solve for "y" (our "second number"):

     2x + 5y = 78 ; (first equation);
     
      5x − y = 33 ; (second equation); 
______________________________
Start with our "second equation"; to solve for "y"; plug in "9" for "x" ;

→ 5(9) − y = 33 ;  

    45 − y = 33;  
   
Add "y" to each side of the equation:
 
   45 − y + y = 33 + y ;  to get:

   45 = 33 + y ;  

↔ y + 33 = 45 ;  Subtract "33" from each side of the equation; to isolate "y" on one side of the equation ; & to solve for "y" ;  
 
 → y + 33 − 33  = 45 − 33 ;

to get:  y = 12 ;

So;  x = 9 ; and y = 12 .  The numbers are:  "9" and "12" .
____________________________________________
 To check our work:
_______________________
1)  Let us plug these values into the original "second equation" ; to see if the equation holds true (with "x = 9" ; and "y = 12") ; 

→ 5x − y = 33 ;  → 5(9) − 12 =? 33 ?? ;  → 45 − 12 =? 33 ?? ;  Yes!
________________________
2)  Let us plug these values into the original "second equation" ; to see if the equation holds true (with "x = 9" ; and "y = 12") ;

→ 2x + 5y = 78 ; → 2(9) + 5(12) =? 78?? ; → 18 + 60 =? 78?? ; Yes!
_____________________________________
So, these answers do make sense!
______________________________________
3 0
3 years ago
Plz help ill give u brainlist
adoni [48]
The problem tells you that a circle with radius 21 inches is painted in two colors. The two colors cover equal areas, so each color is half the area of the circle. You need to find half of the area of the circle. To do that, use the formula for the area of a circle, and then divide by 2.

A = \pi r^2

A = 3.14 \times 21~ inches \times 21~inches

A = 1384.74~square ~inches

Half the circle has area 1384.74 square inches / 2 = 692.37 square inches.

Answer: Each color covers 692.37 square inches.
4 0
3 years ago
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