Ask question

Ask question

All categories

Gelneren [198K]

3 years ago

11

Rectangle A has length 3 and width 5. Rectangle B has length 12 and

1 answer:

galina1969 [7]3 years ago

7 0

Answer:

Yes, the scale factor is 4.

Step-by-step explanation:

If you times the length, 3, and the width, 5, by 4, you'll get 12 as your length and 20 as your width.

You might be interested in

The bottom of Ignacio's desktop is 74.5cm from the floor. Ignacio's sits in his adjustable chair, and the tops of his legs are 4

dsp73

Answer:

Ignacio can make 5 clockwise rotations.

Step-by-step explanation:

Given that the Ignacio's legs are already at a height of 49.3cm and each rotation of the chair knob raises his legs another 4.8cm, we can set up an inequality to determine the number of rotations Ignacio could make without his legs touching the desk, which is at a height of 74.5cm:

4.8r + 49.3 < 74.5 where 'r' is equal to the number of rotations

The sum of the Ignacio's original leg height plus the amount of height increased from the rotations of the know must be less than 74.5 in order for his legs not to touch. Now, solve for 'r':

Subtract 49.3 from both sides: 4.8r + 49.3 - 49.3 < 74.5 - 49.3 or 4.8r < 25.2

Divide 4.8 from both sides: 4.8r/4.8 < 25.2/4.8 or r < 5.25

Since the number of rotations must be less than 5.25, he can make 5 complete rotations.

6 0

3 years ago

Need help please ASAP

Ostrovityanka [42]

Answer:

D

Step-by-step explanation:

You have 4 chairs originally, added 2 and if you separate the tables you would get T=whatever the number is. i think

4 0

3 years ago

What is the difference? startfraction 2 x 5 over x squared minus 3 x endfraction minus startfraction 3 x 5 over x cubed minus 9

weeeeeb [17]

The difference of the expression $\frac{2x^5}{x^2 - 3x} - \frac{3x^5}{x^3 - 9x}$ is $\frac{2x^5(x + 3) - 3x^5}{x(x - 3)(x + 3)}$

<h3>How to determine the difference?</h3>

The expression is given as:

$\frac{2x^5}{x^2 - 3x} - \frac{3x^5}{x^3 - 9x}$

Factor the denominators of the expressions:

$\frac{2x^5}{x(x - 3)} - \frac{3x^5}{x(x^2 - 9)}$

Apply the difference of two squares to x² - 9

$\frac{2x^5}{x(x - 3)} - \frac{3x^5}{x(x - 3)(x + 3)}$

Take LCM

$\frac{2x^5(x + 3) - 3x^5}{x(x - 3)(x + 3)}$

Hence, the difference of the expression $\frac{2x^5}{x^2 - 3x} - \frac{3x^5}{x^3 - 9x}$ is $\frac{2x^5(x + 3) - 3x^5}{x(x - 3)(x + 3)}$

Read more about expressions at:

brainly.com/question/723406

#SPJ4

6 0

2 years ago

What is the simplified form of 3(5V3 + 3V3)?

Rasek [7]

Answer:

$24 \sqrt{3}$

Step-by-step explanation:

$3(5 \sqrt{3} + 3 \sqrt{3} ) \\ \\ = 3(5 + 3 ) \sqrt{3} \\ \\ = 3(8) \sqrt{3} \\ \\ = 24 \sqrt{3}$

8 0

3 years ago

Kendra is a blind marathon runner training for the Junior

mezya [45]

Answer:

Slope = $\frac{1}{5}$

Equation of the line is $y=\frac{x}{5}$

Step-by-step explanation:

Given question is incomplete; find the complete question in the attachment.

Since the given line passes through two points (5, 1) and (10, 2),

Slope of the given line = $\frac{(y_{2}-y_{1})}{(x_{2}-x_{1})}$

m = $\frac{(2-1)}{(10-5)}$

m = $\frac{1}{5}$

Since the given line passes through (10, 2), equation of the line will be

y - y' = m(x - x')

$y - 2=\frac{1}{5}(x-10)$

$y=2+\frac{x}{5}-2$

$y=\frac{x}{5}$

Therefore, equation that can be used to find the distance y from the start after x minutes will be $y=\frac{x}{5}$

7 0

3 years ago