Rectangle A has length 3 and width 5. Rectangle B has length 12 and

Mathematics

1 answer:

galina1969 [7]2 years ago

7 0

Answer:

Yes, the scale factor is 4.

Step-by-step explanation:

If you times the length, 3, and the width, 5, by 4, you'll get 12 as your length and 20 as your width.

You might be interested in

You have an ant farm with 35 ants. The population of ants in your farm will double every 3 months. The table shows the populatio

vfiekz [6]

Answer:

560 ants and non linear function

Step-by-step explanation:

12 months divided by 3 months is 4. 35 times 2 is 70. Again is 140. Again is 280. Again a 4th time is 560 ants. It is not linear because it does not increase the same amount each time.

7 0

2 years ago

Find the ratio of:<br> (a) 5 km to 400 m<br> (b) 2 hours to 160 minutes

aleksandr82 [10.1K]

Answer:

Answer - a) 1:80

b) 1:80

Step-by-step explanation:

All the ratio should be written in lowest form. these are the answers for both the questions.

Pls Mark Brainliest !!!!!!!!!!!!!!

6 0

2 years ago

Read 2 more answers

You are saving money to buy an electric guitar. You deposit $1000 in an account that earns interest compounded annually. The exp

Katena32 [7]

Let's move like a crab, backwards some.

after 2 years?

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$1000\\
r=rate\to 3\%\to \frac{3}{100}\to &0.03\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &2
\end{cases}
\\\\\\
A=1000\left(1+\frac{0.03}{1}\right)^{1\cdot 2}\implies A=1000(1.03)^2$

after 3 years?

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$1000\\
r=rate\to 3\%\to \frac{3}{100}\to &0.03\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &3
\end{cases}
\\\\\\
A=1000\left(1+\frac{0.03}{1}\right)^{1\cdot 3}\implies A=1000(1.03)^3$

is that enough to pay the $1100?

now, let's write 1000(1+r)² in standard form

1000( 1² + 2r + r²)

1000(1 + 2r + r²)

1000 + 2000r + 1000r²

1000r² + 2000r + 1000 <---- standard form.

8 0

2 years ago

DeSean is sorting his toy car collection. ⅔ of the cars are sports cars. ¼ of the remaining toys are pick up trucks. All of the

user100 [1]

Answer:

Fraction of fire trucks = $\frac{1}{4}$