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vichka [17]
3 years ago
5

Unit Test

Mathematics
2 answers:
wolverine [178]3 years ago
4 0

Answer: c the third option

Step-by-step explanation:

Alborosie3 years ago
4 0

Answer:

Hope this helps!

Step-by-step explanation:

cost=flat fee+changing fee

flat fee=5.50

changing fee=cost per ticket times number of tickets

we know that 5 times cost per ticket=108

divide by 5

cost per ticket=21.6

c=number of tickets

total cost=5.5+21.6c

TC=21.6c+5.5

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15

Step-by-step explanation:

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Find y given the following kite
77julia77 [94]

Answer:

y = 32

Step-by-step explanation:

(2y + 3) + 23 + 90 = 180

2y = 64

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3 years ago
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NEED HELP ASAP<br> !!!!!!!
poizon [28]

Answer:

P = 184 yards

C = 175.84 centimetres

P = 212 m

Step-by-step explanation:

P = 2(150 yards) + 2(92 yards)

P = 300 yards + 184 yards

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C = 2(3.14) × (28 centimetres)

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6 0
2 years ago
The graph of F ( x ) = 4/x2 - 2x - 3 is shown <br> for which values of X is f ( x ) decreasing
Elza [17]

Hi there!

\large\boxed{(-\infty, \sqrt[3]{-4}) \text{ and } (0, \infty) }

We can find the values of x for which f(x) is decreasing by finding the derivative of f(x):

f(x) = \frac{4}{x^2} - 2x - 3

Taking the derivative gets:

f'(x) = -\frac{8}{x^3} - 2

Find the values for which f'(x) < 0 (less than 0, so f(x) decreasing):

0 = -8/x³ - 2

2 = -8/x³

2x³ = -8

x³ = -4

x = \sqrt[3]{-4}

Another critical point is also where the graph has an asymptote (undefined), so at x = 0.

Plug in points into the equation for f'(x) on both sides of each x value to find the intervals for which the graph is less than 0:

f'(1) = -8/1 - 2 = -10 < 0

f'(-1) = -8/(-1) - 2 = 6 > 0

f'(-2) = -8/-8 - 2 = -1 < 0

Thus, the values of x are:

(-\infty, \sqrt[3]{-4}) \text{ and } (0, \infty)

6 0
3 years ago
What is the rate of change of the function?
Dominik [7]
I think it would be -3
5 0
3 years ago
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