<u>It doesn't matter what order the coordinates are in the distance formula as long as it stays in it's corresponding order.</u> In this case, (-7,5) could be (x1,y1) and (3,-5) could be (x2,y2) or vise versa, just as long as you don't mix up the coordinates (so no (-7,-5) or (3,5)). I'll demonstrate this below:

<u>The distance between these points, no matter the order, is √200, or approximately 14.14 units.</u>
Answer:
53.8
Step-by-step explanation:
31.5 + 22.3
53.8
Hope it helps
Answer:
The expected value of the winnings for a single-ticket purchase is -$1.0016.
Step-by-step explanation:
The total number of tickets sold is, <em>N</em> = 1250.
Cost of one ticket is, $4.
Let <em>X</em> = amount of prize.
The prize distribution is as follows:
1 Grand price = $3000
1 Second prize = $450
10 Third prize = $25
The expected value <em>X</em> can be computed using the formula:

Compute the probability distribution of <em>X</em> as follows:
Prize Amount (X) P (X) x · P (X)
1 Grand prize $3000

1 Second prize $450

10 Third prize $25

No prize -$4

TOTAL 1.0000 -1.0016
Thus, the expected value of the winnings for a single-ticket purchase is -$1.0016.
Answer:
Step-by-step explanation:
yes....the pair of linear equations has unique solution.....
2x + 3y - 7 = 0 ...... (i)
3x + 2y + 10 = 0 ....... (ii)
on comparing the equation i nd ii with a1x + b1y + c1 = 0
nd a2x + b2y + c2 = 0 reslectively......
a1 = 2 ; b1 = 3 ; c1 = -7
a2 = 3 ; b2 = 2 ; c2 = 10
here....its clear that......
a1 / a2 is not equal to b1 / b2
Therefore the given pair of linear equation have a unique solution........
Karry ran 4.9 miles more than Tricia. I determined the difference but subtracting the miles to see how many more karry ran.<span />