Answer: Its A.) 10y
Step-by-step explanation:
Answer:
The generalisation she can make from her work is that the other two angles of the quadrilateral are supplementary i.e their sum is 180°
Step-by-step explanation:
We are given the following from what she knows
m∠3=2⋅m∠1... 1
m∠2=2⋅m∠4 ... 2
m∠2+m∠3=360 ... 3
From what is given, we can substitute equation 1 and 2 into equation 3 as shown:
From 3:
m∠2+m∠3=360
Substituting 1 and 2 we will have:
2⋅m∠4 + 2⋅m∠1 = 360
Factor out 2 from the left hand side of the equation
2(m∠4+m∠1) = 360
Divide both sides by 2
2(m∠4+m∠1)/2 = 360/2
m∠4+m∠1 = 180°
Since the sum of two supplementary angles is 180°, hence the generalisation she can make from her work is that the other two angles of the quadrilateral are supplementary i.e their sum is 180°
Hi there!
![\large\boxed{f^{-1}(x) = \sqrt[3]{\frac{x+4}{9} } }](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7Bf%5E%7B-1%7D%28x%29%20%3D%20%20%5Csqrt%5B3%5D%7B%5Cfrac%7Bx%2B4%7D%7B9%7D%20%7D%20%7D)
Find the inverse by replacing f(x) with y and swapping the x and y variables:
Isolate y by adding 4 to both sides:
Divide both sides by 9:
Take the cube root of both sides:
![y = \sqrt[3]{\frac{x+4}{9} }\\\\f^{-1}(x) = \sqrt[3]{\frac{x+4}{9} }](https://tex.z-dn.net/?f=y%20%3D%20%5Csqrt%5B3%5D%7B%5Cfrac%7Bx%2B4%7D%7B9%7D%20%7D%5C%5C%5C%5Cf%5E%7B-1%7D%28x%29%20%3D%20%5Csqrt%5B3%5D%7B%5Cfrac%7Bx%2B4%7D%7B9%7D%20%7D)
Answer:
40
Step-by-step explanation:
look at the picure for step by step explanation
Answer:
Mark point E where the circle intersects segment BC
Step-by-step explanation:
Apparently, Bill is using "technology" to perform the same steps that he would use with compass and straightedge. Those steps involve finding a point equidistant from the rays BD and BC. That is generally done by finding the intersection point(s) of circles centered at D and "E", where "E" is the intersection point of the circle B with segment BC.
Bill's next step is to mark point E, so he can use it as the center of one of the circles just described.
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<em>Comment on Bill's "technology"</em>
In the technology I would use for this purpose, the next step would be "select the angle bisector tool."
