Answer:
y=2x+8
Step-by-step explanation:
Answer:
The total surface area of the cube, including the bottom is
22 m squared.
Step-by-step explanation:
a) Data and Calculations:
Side length = 3 m
Side height = 2 m
Side width = 1 m
The total surface area of the cube, including the bottom is given by the formula, 2lw+2lh+2hw), where l = length, w = width, and h = height.
This can also be rewritten as:
2(l*w + l*h + h*w)
= 2 (3*1 + 3*2 + 2*1)
= 2 (3 + 6 + 2)
= 2 (11)
= 22
b) Ernst should know that the surface area of a cube is the sum of the areas of all faces (or surfaces) because it is a 3D shape. Since the cuboid has 6 rectangular faces, Ernest can determine the surface area by adding the areas of all 6 faces or surfaces. Similarly, he can label the length as (l), width as (w), and height as (h) and use the formula, SA=2lw+2lh+2hw, to find the surface area. This formula can also be rewritten as 2(l*w + l*h + h*w).
19,999 because 5 and up round it up, lower than 5 round it down.
Answer:
36 in over 2
Step-by-step explanation:
Answer:
4' x 2' x 1'
Step-by-step explanation:
Collins' cube has a volume of that is the length of any side, x, cubed: Vol = x^3. Since his box has 8^3, we can say that x = 2. <u>[2^3 = 8]</u>
Amil's box has one side that is 2x. That side would be 2*2 = 4 feet. His volume is also 8 ft^3. Amil's box also has a volume of 8 ft^3.
His box dimensions are therefore: (4)(X)(Y) = 8 ft^3 , where X and Y are whole-number dimensions for the other 2 dimensions of his box.
(4)(X)(Y) = 8 ft^3
X*Y = 2
The only combination of whole numbers for which this this would work is 1 and 2.
Amil's box is 4' x 2' x 1' or 8 ft^3
