Answer:
Answer is 18
Step-by-step explanation:
18x3=54
54+54=108
18+2=20
20+20=40
108+40=148
Step-by-step explanation:
14)
Simplifying
3m + 5 = 4m -10
Reorder the terms:
5 + 3m = 4m -10
Reorder the terms:
5 + 3m = -10 + 4m
Solving
5 + 3m = -10 + 4m
Solving for variable 'm'.
Move all terms containing m to the left, all other terms to the right.
Add '-4m' to each side of the equation.
5 + 3m + -4m = -10 + 4m + -4m
Combine like terms: 3m + -4m = -1m
5 + -1m = -10 + 4m + -4m
Combine like terms: 4m + -4m = 0
5 + -1m = -10 + 0
5 + -1m = -10
Add '-5' to each side of the equation.
5 + -5 + -1m = -10 + -5
Combine like terms: 5 + -5 = 0
0 + -1m = -10 + -5
-1m = -10 + -5
Combine like terms: -10 + -5 = -15
-1m = -15
Divide each side by '-1'.
m = 15
Simplifying
m = 15
(thank to <em>geteasysolution</em> . com
15)
xy+yz=xz
a+a+8=50
2a=42
a=21
a+8=29
Answer:
Answer:
Since the calculated value of t= -1.340 does not fall in the critical region , so we accept H0 and may conclude that the data do not provide sufficient evidence to indicate hat there is difference in mean carbohydrate content between "meals with potatoes" and "meals with no potatoes".
Step-by-step explanation:
Potatoes : No Potatoes : Difference Difference (d)²
(Potatoes- No Potatoes)
29 41 -12 144
25 41 -16 256
17 37 -20 400
36 29 -7 49
41 30 11 121
25 38 -13 169
32 39 -7 49
29 10 19 361
38 29 9 81
34 55 -21 441
24 29 -5 25
27 27 0 0
<u>29 31 -2 4 </u>
<u> ∑ -64 2100 </u>
- We state our null and alternative hypotheses as
H0 : μd= 0 and Ha: μd≠0
2. The significance level alpha is set at α = 0.01
3. The test statistic under H0 is
t= d`/sd/√n
which has t distribution with n-1 degrees of freedom.
4. The critical region is t > t (0.005,12) = 3.055
5. Computations
d`= ∑d/n = -64/ 13= -4.923
sd²= ∑(di-d`)²/ n-1 = 1/n01 [ ∑di² - (∑di)²/n]
= 1/12 [2100- ( -4.923)] = 175.410
sd= √175.410 = 13.244
t = d`/sd/√n= - 4.923/13.244/√13
t= - 4.923/3.67344
t= -1.340
6. Conclusion :
Since the calculated value of t= -1.340 does not fall in the critical region , so we accept H0 and may conclude that the data do not provide sufficient evidence to indicate hat there is difference in mean carbohydrate content between "meals with potatoes" and "meals with no potatoes".
Answer:
A) 
B) 
t > s
Step-by-step explanation:
Attached below is a detailed solution of the given problem
Given equation:
dy/dt + ay = 
with Y(c) = 0
A) Determine the solution 
B) Determine the solution 
1 or 3? I don’t really know
