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2 years ago

The cone to the right has a height of 11 in. and a volume of

Mathematics

1 answer:

Contact [7]2 years ago

8 0

Answer:

2.99924 in

Step-by-step explanation:

Volume of a cone

V = pi x r^2 x h/3

So to solve this problem you plug in the number we already have which is the volume and the height

103.62 = pi x r^2 x 11/3

28.26 = pi x r^2

28.26/pi = r^2

$\sqrt{\frac{28.26}{\pi } }$ = r ≈ 2.99924

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Line ef is tangent to circle G at point P. The the measure of cae is 95, what is the measure of cba

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Answer: the answers 190

Step-by-step explanation:

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3 years ago

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The volume of the above solid is?

Novosadov [1.4K]

B of course i think i hope

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3 years ago

The force, F (Newtons), between two objects is inversely proportional to the square of the distance, d (metres), between them.

snow_lady [41]

Answer:

d = 1.46 m

Step-by-step explanation:

We'll begin by obtaining the relationship between the force (F) and the distance (d). This can be obtained as follow:

From the question given above,

F is inversely proportional to square of d. This can be written as:

F ∝ 1/d²

F = K/d²

Cross multiply

K = Fd²

But:

Force (F) = 0.006 N

Distance (d) = 4 m

Constant (K) =?

K = Fd²

K = 0.006 × 4²

K = 0.006 × 16

K = 0.096 Nm²

Therefore, the relationship between the force (F) and the distance (d) is:

F = K/d²

F = 0.096 / d²

Finally, we shall determine the distance when the force is 0.045 N. This can be obtained as follow:

Force (F) = 0.045 N

Constant (K) = 0.096 Nm²

Distance (d) =?

F = K/d²

0.045 = 0.096 / d²

Cross multiply

0.045 × d² = 0.096

Divide both side by 0.045

d² = 0.096 / 0.045

Take the square root of both side.

d = √(0.096 / 0.045)

d = 1.46 m.

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2 years ago

Can someone please help me?

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Answer:

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Step-by-step explanation:

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3 years ago

Let f(x) = cx^k be a power function such that f(13) is four times the size of f(1). What is the power k?

Ivenika [448]

Answer:

0.540

Step-by-step explanation:

Hi there,

To get started in order to solve this, please recall the property of logarithms.

This question is a bit tricky, but doable. Best way to solve this is first compare the two functions:

$f(x) = cx^{k} \\ f(13)=4f(1)$

Now, let's see what the function gives at 13 and 1:

$f(13)=c13^{k}\\f(1)=c1^{k}$

Something to recognize is that 1 to the power of <em>anything</em> is just 1, so f(1) is reduced to:

$f(1)=c$ We are making progress!

Next, we can set both f(13) forms equivalent to each other, watch this:

$f(13)=f(13) = 4f(1)$ but we know what f(1) is equal to, and let's substitute our knowns:

$c13^{k}=4c1^{k} = 4c$ the c constant on both left and right side cancel out:

$13^{k}=4$ Now, take the logarithm form of both side of the equation. I used natural log, but you can also use common logs:

$ln(13^{k})=ln(4)$ ⇒ $k*ln(13)=ln(4)$ this was performed using <em>the power log rule. </em>

Isolate k:

$k=\frac{ln(4)}{ln(13)} =0.540$ using a calculator.

If you liked this solution, hit Thanks or give a rating!

thanks,

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2 years ago