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nirvana33 [79]
3 years ago
10

PLEASE HELP ! <3 !!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
svlad2 [7]3 years ago
5 0

Answer:

7 things an investor should consider when picking stocks:

Trends in earnings growth.

Company strength relative to its peers.

Debt-to-equity ratio in line with industry norms.

Price-earnings ratio as an indicator of valuation.

How the company treats dividends.Effectiveness of executive leadership.

Step-by-step explanation:

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A relay race is 1 3 4 miles long. Each relay team has 4 runners. If each runner runs the same distance in the race, how far will
Vika [28.1K]

Answer: 7/16

Step-by-step explanation:

Distance of the relay race = 1 3/4 miles

Number of runners for the relay team = 4 runners

Distance to be run by each runner will be:

= Distance of the relay race / Number of runners

= 1 3/4 ÷ 4

= 7/4 ÷ 4

= 7/4 × 1/4

= 7/16

Each runner will run 7/16 miles

6 0
3 years ago
A boy of mass 8000g climbed a tree of height 5.5 m calculate a.the weight of the boy. b.the work done by the boy​
katrin [286]

Answer:

put it in pounds then i can help

Step-by-step explanation:

8 0
3 years ago
The oil prices for 2014, rounded to the nearest dollar, were: 95, 101, 101, 102, 102, 106, 104, 97, 93, 84, 76, 59. what is the
kipiarov [429]
  • Interquartile Range (IQR) = Q_3-Q_1 , with Q_3 as the upper quartile and Q_1 as the lower quartile.

Firstly, rearrange the data so that it's in ascending order: \{59,76,84,93,95,97,101,101,102,102,104,106\}

Next, find the median:

\{59,76,84,93,95,\boxed{97,101,}101,102,102,104,106\}\\\\\frac{97+101}{2}\\\\\frac{198}{2}\\\\99

Now to find the lower quartile, find the "median" of the data set that's to the left of 99:

\{\overbrace{59,76,84,93,95,97}^{\textsf{to the left of the median}},101,101,102,102,104,106\}\\\\\{\overbrace{59,76,\boxed{84,93}95,97}^{\textsf{to the left of the median}},101,101,102,102,104,106\}\\\\\frac{84+93}{2}\\\\\frac{177}{2}\\\\88.5

Now to find the upper quartile, it's the similar process as finding the lower quartile, except that you are finding the "median" of the data set to the right of 99:

\{59,76,84,93,95,97,\overbrace{101,101,102,102,104,106}^{\textsf{to the right of the median}}\}\\\\\{59,76,84,93,95,97,\overbrace{101,101,\boxed{102,102} 104,106}^{\textsf{to the right of the median}}\}\\\\\frac{102+102}{2}\\\\\frac{204}{2}\\\\102

Now that we have the upper and lower quartile, subtract them:

102-88.5=13.5

<u>In short, the IQR of this data set is 13.5.</u>

8 0
3 years ago
Preston works in a bakery where he puts muffins in boxes. He makes the following table to remind himself how many blueberry muff
Natasha_Volkova [10]
It is being multiplied by 3. blueberry muffins ×3 = total # of muffins,so the answer would be 12
8 0
3 years ago
Read 2 more answers
Graph the image of this figure after a dilation with a scale factor of 2 centered at the origin.
pshichka [43]

Answer:

(2,4), (6,4), (2,-2), (6,-2)

Step-by-step explanation:

To dilate a figure multiply 2(x,y)

2(1,2)  = (2,4)

2(3,2) = (6,4)

2(1,-1) = (2,-2)

2(3,-1) = (6,-2)

Hope this helps!   Ξ

3 0
3 years ago
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