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3 years ago

Solve S=2πrh+πr2 for h

1 answer:

3 0

$S= \pi rh+ \pi r^2\ \ \ \ | subtract\ \pi r^2\\\\
s-\pi r^2= \pi rh\ \ \ \ | divide\ by\ \pi r \\\\
\frac{s-\pi r^2}{ \pi r}=h$

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lana66690 [7]

The answer is:

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Then add 4 and you should get the correct number for each y value.

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2 years ago

Find the inverse function of f informally. f(x) = 6x

yaroslaw [1]

$f^-^1(x) = \frac{x}{6}$

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3 years ago

a card is chosen from a standard deck of cards. what is the probability that the card is a queen, given that the card is a club?

Dmitrij [34]

Answer:

Probability that card is queen given that card is club is $\frac{4}{13}$

Step-by-step explanation:

Given : A card is chosen from a standard deck of cards.

To find : What is the probability that the card is a queen, given that the card is a club?

Solution : It is the conditional probability

$P(A|B)=\frac{P(A\cap B)}{P(B)}$

Let A is probability that card is queen.

Let B is the probability that card is a club.

Probability that card is queen given card is club $P(A\cap B)=\frac{4}{52}=\frac{1}{13}$

Probability that card is club from deck of 52 cards $P(B)=\frac{13}{52}=\frac{1}{4}$

To find probability that card is queen given that card is club $P(A|B)$

$P(A|B)=\frac{P(A\cap B)}{P(B)}$

$P(A|B)=\frac{\frac{1}{13}}{\frac{1}{4}}$

$P(A|B)=\frac{1\times4}{13\times 1}=\frac{4}{13}$

Therefore, Option A is correct.

Probability that card is queen given that card is club is $\frac{4}{13}$

7 0

3 years ago

Read 2 more answers

Here are five straight line graphs.

Evgen [1.6K]

y=x e

x=3 b

x+y=3 A

i think

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2 years ago

Write an equivalent

erma4kov [3.2K]

Answer:

By substituting the value of the variable and simplifying it with the equation you get 158.

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2 years ago