3 years ago

Solve S=2πrh+πr2 for h

1 answer:

3 0

$S= \pi rh+ \pi r^2\ \ \ \ | subtract\ \pi r^2\\\\
s-\pi r^2= \pi rh\ \ \ \ | divide\ by\ \pi r \\\\
\frac{s-\pi r^2}{ \pi r}=h$

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The discriminant of a quadratic is $b^2-4ac$ , where the quadratic is in the form $ax^2+bx+c$ . The discriminant of this one is therefore:

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