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2 years ago

HELPPPP MEEEEE!!!!!!!

Mathematics

1 answer:

Kipish [7]2 years ago

3 0

Answer:

Rounded:

596.05

596.046

Raw:

596.046447754

Step-by-step explanation:

Solved with sci calculator

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WILL GIVE BRAINLIEST

dalvyx [7]

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D. 8pi>24 cause this is the right answer

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2 years ago

Nineteen students were invited to michelle's party. Three more boys than girls were invited. How many boys were invited?

bekas [8.4K]

11 boys and 8 girls because you divide it in half the add 2 and subtract 1. That isn't the wy you are supposed to do it but it works and makes since in my head.

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3 years ago

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Hello ! I need a solution for this exercise: either 1≤x≤2 and let A = -3 + 8 / (x + 1) -2x² Show that -9≤A≤-1

Phantasy [73]

\left[A \right] = \left[ \frac{ - \left( 5 - 3\,x - 2\,x^{2} - 2\,x^{3}\right) }{-1-x}\right][A]=[−1−x−(5−3x−2x2−2x3)] I hope helping this answer

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3 years ago

What is the midpoint of line segment AB?

Elza [17]

Answer

Midpoint = (3, 5.5)

Step by step explanation

Here we have to use the midpoint formula.

Midpoint = ( $\frac{x1 + x2}{2} , \frac{y1 + y2}{2} \\$ )

Here the point A = (-1, 8) and B = (7, 3)

x1 = -1, y1 = 8, x2 = 7 and y2 = 3

Now plug in these values into the formula.

Midpoint = ( $\frac{-1 + 7}{2} , \frac{8 + 3}{2}$

= (6/2, 11/2)

= (3, 5.5)

Therefore, the midpoint the line segment AB is (3, 5.5)

Thank you.

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3 years ago

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WORTH 20 POINTS HELP

vfiekz [6]

Below represents the proof that the quadrilateral QRST is a parallelogram

<h3>How to prove that QRST is a parallelogram?</h3>

The coordinates are given as:

Q = (-1,-1)

R = (2,9)

S = (-4,5)

T = (-7,-5)

Calculate the length of each side using:

$d = \sqrt{(x_2 -x_1)^2 + (y_2 -y_1)^2}$

So, we have:

$QR = \sqrt{(-1 - 2)^2 + (-1 -9)^2} = \sqrt{109}$

$RS = \sqrt{(-4 - 2)^2 + (5 - 9)^2} = \sqrt{52}$

$ST = \sqrt{(-7 + 4)^2 + (-5 - 5)^2} = \sqrt{109}$

$TQ = \sqrt{(-7 + 1)^2 + (-5 + 1)^2} = \sqrt{52}$

The above computations show that opposite sides are equal.

Next, we determine the slope of each side using:

$m = \frac{y_2 -y_1}{x_2 -x_1}$

So, we have:

$QR = \frac{9 + 1}{2 + 3} = \frac{10}3$

$RS = \frac{5-9}{-4 - 2} = \frac{2}3$

$ST = \frac{5+5}{-4 + 7} = \frac{10}3$

$TQ = \frac{-5+1}{-7 + 1} = \frac{2}3$

The above computations show that opposite sides are parallel, because they have equal slope

Hence, the quadrilateral QRST is a parallelogram