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3 years ago

7

I really need help with this math problem!!

1 answer:

san4es73 [151]3 years ago

4 0

The answer is A. y = -2x +3

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Find the value of x so that the line passing through the points will have the given slope: (x,6) and (10,-3) with a slope of -3/

Lana71 [14]

$(x,6) \\
x_1=x \\
y_1=6 \\ \\
(10,-3) \\
x_2=10 \\ y_2=-3 \\ \\
\hbox{the slope: } m=\frac{y_2-y_1}{x_2-x_1}=\frac{-3-6}{10-x}=\frac{-9}{10-x} \\ \\
m=-\frac{3}{2} \\
\Downarrow \\
-\frac{3}{2}=\frac{-9}{10-x} \\
-\frac{3}{2}(10-x)=-9 \\
10-x=-9 \times (-\frac{2}{3}) \\
10-x=3 \times 2 \\
10-x=6 \\
-x=6-10 \\
-x=-4 \\
\boxed{x=4}$

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3 years ago

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galben [10]

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3 years ago

Read 2 more answers

Multiply. Write your answer in simplest form.<br><br> 7 x 3/4

sweet-ann [11.9K]

If you would like to calculate 7 * 3/4, you can do this using the following steps:

7 * 3/4 = 21/4 = 5 1/4

The correct result would be 21/4.

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3 years ago

Suppose that A and B are points on the number line.

oksian1 [2.3K]

Answer:

Suppose that A and B are points on the number line.

If AB=11 and A lies at 6, where could B be located?

If there is more than one location, separate them with commas

Step-by-step explanation:

Suppose that A and B are points on the number line.

If AB=11 and A lies at 6, where could B be located?

If there is more than one location, separate them with commas

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3 years ago

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Alexxandr [17]

Answer:

Step-by-step explanation:

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3 years ago