I really need help with this math problem!!

Mathematics

1 answer:

san4es73 [151]3 years ago

4 0

The answer is A. y = -2x +3

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Solve for x 0.5(5−7x)=8−(4x+6) x = ???

leonid [27]

Hello!

0.5 (5 - 7x) = 8 - (4x+6)
2.5 - 3.5x = 8 - 4x + 6
2.5 - 3.5x = 2 - 4x
-3.5x + 4x = 2 - 2.5
0.5x = -0.5
X = -1

Your answer is x = -1. I hope this helps!

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3 years ago

Angles 1 and 2 are supplementary.

Phantasy [73]

Answer:

m∡1 + m∡2 = 180

Step-by-step explanation:

m∡1 + m∡2 = 180

This is because supplementary means they add up to 180°.

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3 years ago

I need help with number 12

FrozenT [24]

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3 years ago

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Use the triangles to answer the question. if △ABC ≅ △FDE, what is the measure of ∠ACB?

Nadya [2.5K]

The answer to what is the measure of ∠acb is 34.7

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3 years ago

a 16 inch wire is to be cut. one piece is to be bent into the shape of a square, whereas the other piece is to be bent into the

Lyrx [107]

1. Let x be a length of square side, then the square perimeter is 4x (you need to cut 4x from 16 in. to make a square with side x in.). Then 16-4x is remained length of wire and you have to make form this piece a rectangle with sides one of which is twice bigger than another. If y is length of the smaller side, then 2y is length of the bigger side and rectangle perimeter is y+2y+y+2y=6y. You have 16-4x in. of wire left, so 6y=16-4x and $y= \frac{16-4x}{6}$ .

2.
$A_{square}=x^2 \\ A_{rectangle}=y\cdot 2y=\frac{16-4x}{6}\cdot2\cdot\frac{16-4x}{6}= \frac{(16-4x)^2}{18} \\ A(x)=A_{square}+A_{rectangle}=x^2+\frac{(16-4x)^2}{18}$ .

3. Find the derivative of the function A(x):
$A'(x)=2x+ \dfrac{2(16-4x)\cdot(-4)}{18} =2x- \dfrac{4(16-4x )}{9}$ .

4. Solve the equation A'(x)=0:
$2x- \dfrac{4(16-4x )}{9}=0 \\ 18x-64+16x=0 \\ 34x=64 \\ x= \frac{32}{17}$

5. Since $y= \frac{16-4x}{6}$ you have

$y= \dfrac{16-4 \frac{32}{17} }{6} = \dfrac{16\cdot17-4\cdot32}{6\cdot 17} = \dfrac{24}{17}$ .

Answer: the width of the rectangle is $\frac{24}{17}$

6 0

4 years ago