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3 years ago

I really need help with this math problem!!

Mathematics

1 answer:

san4es73 [151]3 years ago

4 0

The answer is A. y = -2x +3

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What’s the lowest common multiple of 120 and 75

andreyandreev [35.5K]

<h2>Answer: 600</h2>

Step-by-step explanation:

prime factorization of 75:

75 = 3 × 5 × 5

prime factorization of 120:

120 = 2 × 2 × 2 × 3 × 5

LCM = 2 × 2 × 2 × 3 × 5 × 5

There for the LCM = 600

* HOPEFULLY THIS HELPS:) Mark me the brainliest:)!!

5 0

4 years ago

10. If possible, determine whether or not triangles LQP and LMN

natita [175]

Answer:

They are similar

Step-by-step explanation:

If two triangles are similar, the ratio of their corresponding side lengths must be equal to each other.

This means that for ∆LQP and ∆LMN to be considered similar to each other, therefore:

LM/LQ = LN/LP

LM = 100

LQ = 12

LN = 75

LP = 9

LM/LQ = 100/12 = 25/3

LN/LP = 75/9 = 25/3

LM/LQ = LN/LP = 25/3, therefore ∆LQP and ∆LMN are similar to each other because the ratio of their corresponding side lengths are the same.

3 0

3 years ago

A jumbo crayon is composed of a cylinder with a conical tip. The cylinder is 12 cm tall with a radius of 1.5 cm, and the cone ha

s2008m [1.1K]

Answer:

Part 1) The lateral area of the cone is $LA=2\pi\ cm^{2}$

Part 2) The lateral surface area of the cylinder is $LA=36\pi\ cm^{2}$

Part 3) The surface area of the crayon is $SA=41.50\pi\ cm^{2}$

Step-by-step explanation:

Part 1) Find the lateral area of the cone

The lateral area of the cone is equal to

$LA=\pi rl$

we have

$r=1\ cm$

$l=2\ cm$

substitute

$LA=\pi (1)(2)$

$LA=2\pi\ cm^{2}$

Part 2) Find the lateral surface area of the cylinder

The lateral area of the cylinder is equal to

$LA=2\pi rh$

we have

$r=1.5\ cm$

$h=12\ cm$

substitute

$LA=2\pi (1.5)(12)$

$LA=36\pi\ cm^{2}$

Part 3) Find the surface area of the crayon

The surface area of the crayon is equal to the lateral area of the cone, plus the lateral area of the cylinder, plus the top area of the cylinder plus the bottom base of the crayon

<em>Find the area of the bottom base of the crayon</em>

$A=\pi[r2^{2}-r1^{2}]$

where

r2 is the radius of the cylinder

r1 is the radius of the cone

substitute

$A=\pi[1.5^{2}-1^{2}]$

$A=1.25\pi\ cm^{2}$

<em>Find the area of the top base of the cylinder</em>

$A=\pi(1.5)^{2}=2.25\pi\ cm^{2}$

<em>Find the surface area</em>

$SA=2\pi+36\pi+2.25\pi+1.25\pi=41.50\pi\ cm^{2}$

8 0

3 years ago

Read 2 more answers

Factor the polynomial. 8x^2 - 50

blsea [12.9K]

2 • (2x + 5) • (2x - 5)

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3 years ago

Hottest centralisation

dsp73

Answer:

centralisation mean a direction explain that we often a high how well we cancan predict future actions of others.

Step-by-step explanation:

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3 years ago