Answer:
1.10
Step-by-step explanation:
Answer:
e. 
Step-by-step explanation:
It is given that,
The density of intergalactic space material is
kg per cubic meter.
And the volume of intergalactic space material is 
So the mass of that much intergalactic space material is,
, where 'm' is the mass, and 'v' is the volume.
Putting the values we get,


It is also given that the mass of lead is the same as the mass of the intergalactic space material. Therefore, the mass of lead is 
So the volume of lead is,


So the volume of lead is
.
Answer:
1/4
Step-by-step explanation:
there are 12 gumballs in total
1 yellow + 2 pink = 3 gumballs out of all 12
3 /12 is simplified to 1/4 as both numbers is divisible by 3
2 and 3 are both parallel because both slopes are m=3/5, which equal slopes-parallel lines
Answer: x=5
Step-by-step explanation:
If you break the fraction into a whole number it would be 5 and 10 minus 5 is 5. so x=5