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Advocard [28]
2 years ago
5

A car travels a distance of D km at 80 km/h and arrives 20 min late. If the car travels at

Mathematics
1 answer:
Leya [2.2K]2 years ago
4 0
It’s would be 160 km since 160/80x60=120 min and 160/120x60=80min
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Solving linear systems of substitution
never [62]
Example: 2x+2y=8 and 3y+2x=6
Okay so u first want to put on of the equations into a y= form. So let's use 3y+2x=6. Subtract 2x from both sides. 3y=6-2x divide by 3. Y= 6-2/3x or y= -2/3x + 6. Now just plug this new equation in for Y since "y=" into the other equation.
2x + 2(-2/3x + 6) = 8.
Then you would distribute the 2 into the parenthesis and simplify to solve for x.
After you solve for x, plug x into one of the original equations to find y.
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3 years ago
Use a proportion to solve:
Mariulka [41]

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420 miles

Step-by-step explanation:

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3 years ago
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A pyramid has a square base of length 8cm and a total surface area of 144cm². Find the volume of the pyramid. (Please use Pythag
Sveta_85 [38]

Answer:

\displaystyle V_{ \text{pyramid}}= 64 \:  {cm}^{3}

Step-by-step explanation:

we are given surface area and the length of the square base

we want to figure out the Volume

to do so

we need to figure out slant length first

recall the formula of surface area

\displaystyle A_{\text{surface}}=B+\dfrac{1}{2}\times P \times s

where B stands for Base area

and P for Base Parimeter

so

\sf\displaystyle \: 144=(8 \times 8)+\dfrac{1}{2}\times (8 \times 4) \times s

now we need our algebraic skills to figure out s

simplify parentheses:

\sf\displaystyle \: 64+\dfrac{1}{2}\times32\times s = 144

reduce fraction:

\sf\displaystyle \: 64+\dfrac{1}{ \cancel{ \: 2}}\times \cancel{32}  \: ^{16} \times s = 144 \\ 64 + 16 \times s = 144

simplify multiplication:

\displaystyle \: 16s + 64 = 144

cancel 64 from both sides;

\displaystyle \: 16s = 80

divide both sides by 16:

\displaystyle \: \therefore \: s = 5

now we'll use Pythagoras theorem to figure out height

according to the theorem

\displaystyle \:  {h}^{2}  +  (\frac{l}{2} {)}^{2}  =  {s}^{2}

substitute the value of l and s:

\displaystyle \:  {h}^{2}  +  (\frac{8}{2} {)}^{2}  =  {5}^{2}

simplify parentheses:

\displaystyle \:  {h}^{2}  +  (4 {)}^{2}  =  {5}^{2}

simplify squares:

\displaystyle \:  {h}^{2}  +  16  =  25

cancel 16 from both sides:

\displaystyle \:  {h}^{2}   =  9

square root both sides:

\displaystyle \:   \therefore \: {h}^{}   =  3

recall the formula of a square pyramid

\displaystyle V_{pyramid}=\dfrac{1}{3}\times A\times h

where A stands for Base area (l²)

substitute the value of h and l:

\sf\displaystyle V_{ \text{pyramid}}=\dfrac{1}{3}\times  \{8 \times 8 \}\times 3

simplify multiplication:

\sf\displaystyle V_{ \text{pyramid}}=\dfrac{1}{3}\times  64\times 3

reduce fraction:

\sf\displaystyle V_{ \text{pyramid}}=\dfrac{1}{ \cancel{ 3 \: }}\times  64\times \cancel{ \:  3}

hence,

\sf\displaystyle V_{ \text{pyramid}}= 64 \:  {cm}^{3}

8 0
2 years ago
Homework Week 13 and 14<br> Introduction to Inequalities
irina [24]

Answer:

you are going to have to look from left to right and see if it is above or below

7 0
2 years ago
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