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kolbaska11 [484]
3 years ago
5

Solving linear systems of substitution

Mathematics
1 answer:
never [62]3 years ago
6 0
Example: 2x+2y=8 and 3y+2x=6
Okay so u first want to put on of the equations into a y= form. So let's use 3y+2x=6. Subtract 2x from both sides. 3y=6-2x divide by 3. Y= 6-2/3x or y= -2/3x + 6. Now just plug this new equation in for Y since "y=" into the other equation.
2x + 2(-2/3x + 6) = 8.
Then you would distribute the 2 into the parenthesis and simplify to solve for x.
After you solve for x, plug x into one of the original equations to find y.
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