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1 year ago

10 Find the standard equation of the circle having the given center and radius.

Mathematics

1 answer:

xz_007 [3.2K]1 year ago

8 0

the standard equation of the circle having the given center and radius is $(x-9)^2+(y-2)^2=\frac{9}{25}$ .

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2 years ago

Simplify. 5/4 x 6/12 + 6/5

Aneli [31]

PEMDAS
5/4*6/12=30/48=5/8
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2 years ago

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2 years ago

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Factorise completely. 4 x y squared - 6 y cubed

DanielleElmas [232]

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2 years ago

Please help…………..i have more to ask

ololo11 [35]

Answer:

YES

Step-by-step explanation:

Find each length using the distance formula, $d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

✔️Distance between A(-4, 2) and B(1, 4):

$AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$A(-4, 2) = (x_1, y_1)$

$B(1, 4) = (x_2, y_2)$

$AB = \sqrt{(1 - (-4))^2 + (4 - 2)^2}$

$AB = \sqrt{(5)^2 + (2)^2}$

$AB = \sqrt{25 + 4}$

$AB = \sqrt{29}$

✔️Distance between C(2, -1) and D(4, 4):

$CD = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$C(2, -1) = (x_1, y_1)$

$D(4, 4) = (x_2, y_2)$

$CD = \sqrt{(4 - 2)^2 + (4 - (-1))^2}$

$CD = \sqrt{(2)^2 + (5)^2}$

$CD = \sqrt{4 + 25}$

$CD = \sqrt{29}$

AB = CD = √29

Therefore, they both have the same length.

4 0

3 years ago