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kozerog [31]
3 years ago
6

Can someone help me please I am losing my mind

Mathematics
1 answer:
Blizzard [7]3 years ago
7 0

Answer:

5-x

Step-by-step explanation:

you will simplify the eq. it will be (x+8)-(x+8)(x-4)

taking (x+8) as common(1-x+4)

(x+8)(5-x)

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Y to the 3rd power times y to the negative 5th power
lina2011 [118]
Y^3 * y^5 = y^8. you add the exponents
8 0
3 years ago
Solve the quadratic equation. (x + 6)2 = 49
kykrilka [37]

Answer:

C

Step-by-step explanation:

To solve, use inverse operations:

(x+6)^2=49\\\sqrt{(x+6)^2} =\sqrt{49} \\x+6=+/-7

Now we solve for both +/- 7.

x+6=7

x=1

x+6=-7

x=-13

3 0
3 years ago
In order to remove water from a flooded basement, two pumps, each rated at 40 gallons per minute, are used. After half an hour,
Scrat [10]

Answer:

3600 gallons of water was removed from the basement.

Step-by-step explanation:

Given:

Rate of each pump = 40 gallons/min

We need to find find the number of gallons of water removed from the basement.

Solution:

Now Given:

After half an hour, the one pump burns out.

Now we know that;

1 hour = 60 mins

\frac12 hour = \frac{60}{2}=30\ mins

Now for 30 mins both the pumps were working and removing the water.

So we can say that;

Water remove for first 30 mins = 40\times2\times30=2400\ gallons

Also Given:

the second pump finishes removing the water half an hour later.

So we can say that;

Water removed for next 30 mins = 40\times 30\times1 =1200\ gallons

Now we can say that;

Total water removed from the basement is equal to sum of Water remove for first 30 mins and Water removed for next 30 mins .

framing in equation form we get;

Total water removed from the basement = 2400+1200=3600\ gallons.

Hence 3600 gallons of water was removed from the basement.

6 0
3 years ago
What are the dimensions of the poster at 1/2 it’s current size
Zarrin [17]
C I think I hope I’m right but it should be c
8 0
2 years ago
0.2(x + 15) = 0.5(3x - 7)
Dafna1 [17]
Are you asking if this is greater than, less than, or equal to?
8 0
3 years ago
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