Three times a number decreased by 2 equals forty
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If m ACD = 30 => m DCB = 60.
In triangle ACD:
AC^{2}+CB^{2}=AB^{2} => AB=
=32.
=> P=16+32+
=48 +.
In triangle ACD:
AC^{2}+CB^{2}=AB^{2} => AB=
=> P=16+32+