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3 years ago

P(5. - 5), y=3x+3 Write an equation for the line in point-slope form

Mathematics

2 answers:

Virty [35]3 years ago

5 0

Answer:

y+5 =3(x-5)

Step-by-step explanation:

The point slope form of an equation is : y-y₁ = m(x-x₁)

Given in the question ;

x₁= 5

y₁ = -5

y= 3x+3 where m=3

The equation is :

y-y₁ = m(x-x₁)

y--5 =3(x-5)

y+5 =3(x-5) ----equation of the line in point-slope form.

jolli1 [7]3 years ago

3 0

Answer:

M= 3

Step-by-step explanation:

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Why is the number of operators per shift multiplied by approximately 4.5 to obtain the total number of operators required to run

4vir4ik [10]

I believe you meant "why is the number of shifts multiplied by approximately 4.5 to obtain the total number of operators required to run the plant"

Answer and Explanation:

There are 3 shifts per day, 49 weeks per year and 5 shifts per operator per week

To get total number of operators required to run the plant, we multiply number of shifts in a year by number if operators per shift.

49 weeks×5 shifts= 245 shifts per operator per year

365×3 shifts= 1095 shifts per year

1095/245=4.5 operators per shift

total number of operators required to run the plant(per day) = 4.5×3= 13.5 approximately 14

total number of operators required to run the plant(per year) =4.5×1095=4927.5 approximately 4928

3 0

3 years ago

Disregarding wind resistance the distance a body falls from rest varies directly as th squares of the time it falls if a skydive

Firdavs [7]

Answer:

The skydiver will fall 1600 ft in 10 seconds.

Step-by-step explanation:

<u>Distance a body falls from rest varies directly as the squares of the time it falls </u>

Let distance = s

time = t

Therefore , s = k $\times t^{2}$

Given, the body falls 64 ft in 2 seconds.

Substituting in above equation,

64 = k $\times (2)^{2}$

64 = k $\times (4)$

k = $\frac{64}{4}$

k = 16 ft/ $s^{2}$

We have to find how much he will fall in 10 seconds.

s = k $\times t^{2}$

s = $16 \times 10^{2}$

s = $16 \times 100$

s = 1600 ft

3 0

3 years ago

Please help me with theses 4 questions

MA_775_DIABLO [31]

1. 864 mm^3
2.1640 cm^3
3. 4.0 cm
4. 150pi ft^3

3 0

3 years ago

You start at (3, 0). You move down 5 units and right 1 unit. Where do you end?

nevsk [136]

Answer:

Pretty sure it's (4, -5)

Step-by-step explanation:

If not, shoot me I guess.

8 0

3 years ago

A sample of gold has a mass of 579 g. The volume of the sample is 30 cm3. What is the density of the gold sample?

Ugo [173]

The density of the gold sample is 19.3g/cm³

Let the mass of the gold sample be represented by m

m = 579 g

Let the volume of the gold sample be represented by V

V = 30 cm³

Let the density of the gold sample be represented by ρ

The formula for the density is:

$Density = \frac{Mass}{Volume}$

$\rho = \frac{m}{V} \\\rho = \frac{579}{30} \\\rho = 19.3 g/cm^3$

The density of the gold sample is 19.3g/cm³

Learn more here: brainly.com/question/17780219

3 0

2 years ago