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lidiya [134]
3 years ago
11

P(5. - 5), y=3x+3 Write an equation for the line in point-slope form

Mathematics
2 answers:
Virty [35]3 years ago
5 0

Answer:

y+5 =3(x-5)

Step-by-step explanation:

The point slope form of an equation is : y-y₁ = m(x-x₁)

Given in the question ;

x₁= 5

y₁ = -5

y= 3x+3 where m=3

The equation is :

y-y₁ = m(x-x₁)

y--5 =3(x-5)

y+5 =3(x-5) ----equation of the line in point-slope form.

jolli1 [7]3 years ago
3 0

Answer:

M= 3

Step-by-step explanation:

l2ecdnienofnweucon fuovnewdionsdv wqueijncqodi

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Answer:

B. f(-4) = g(-4), and f(0) = g(0)

Step-by-step explanation:

We are given two functions that have been graphed already. The points on the coordinate plane  where the  curve of g(x) intercepts that of f(x), are the values of x for each function, that would give us the same output (y).

Thus, for f(x) intercepts g(x) at the point where x = -4, y = 4.

Also, f(x) and g(x) intercepts at the point where x = 0, y = 4.

Therefore, the correct answer is f(-4) = g(-4), and f(0) = g(0)

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Round 0.5289 to the nearest thousandth.
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Answer:

0.5289 to the nearest thousandth is 0.529.

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Cho tam giác ABC cân tại A trung tuyến AM.Biết BC=6cm,AM=4cm .Tính độ dài các cạnh AB và AC
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Vì tam giác ABC cân tại A (gt) mà AM là đg trung tuyến nên AM đồng thời là đg cao của t/giác đó:

AM là trung tuyến của t/giác ABC nên M là trung điểm BC:

=> BM =BC/2 =6:2=3(cm)

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3 years ago
A track star runs two races on a certain day. The probability thathe wins the first race is 0.7, the probability that he wins th
NARA [144]

Answer:

a) 80% probability that he wins at least one race.

b) 30% probability that he wins exactly one race.

c) 20% probability that he wins neither race.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that he wins the first race.

B is the probability that he wins the second race.

C is the probability that he does not win any of these races.

We have that:

A = a + (A \cap B)

In which a is the probability that he wins the first race but not the second and A \cap B is the probability that he wins both these races.

By the same logic, we have that:

B = b + (A \cap B)

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This means that A \cap B = 0.5

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There is an 80% probability that he wins at least one race.

B) he wins exactly one race.

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C) he wins neither race

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From a), we have that there is an 80% probability that he wins at least one race.

So there is a 100-80 = 20% probability that he wins neither race.

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