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faust18 [17]
1 year ago
13

29 mint plants and 29 other herb plants at the garden center. Considering this data, how many of the next 62 herb plants stocked

should you expect to be mint plants
Mathematics
1 answer:
spin [16.1K]1 year ago
7 0

Answer: 31 mint plants

Step-by-step explanation:

         We will have mint plants over total plants:

29/29+29 = 29/58 = 1/2

         Now, we will multiply 62 by 1/2 to guess how many mint plants will be stocked.

62* 1/2 = 31

  We should expect about 31 plants of the total plants to be mint plants.

You might be interested in
If g(x)=11x+3 find g(x+7) and g(x)+g(7).
Liono4ka [1.6K]

Answer:

g(x + 7) = 11x + 80

g(x) + g(7) = 11x + 83

Step-by-step explanation:

g(x + 7) = 11(x + 7) + 3 = 11x + 77 + 3 = 11x + 80

g(x) + g(7) = 11x + 3 + 11(7) + 3 = 11x + 3 + 77 + 3 = 11x + 83

8 0
3 years ago
Simplify the expression shown. You must show your work to receive credit.
ZanzabumX [31]

ANSWER

12 \sqrt{5}

EXPLANATION

The given expression is

\sqrt{2}  \times  \sqrt{72}  \times  \sqrt{5}

The middle radical contains a perfect square.

\sqrt{2}  \times  \sqrt{36 \times 2}  \times  \sqrt{5}

\sqrt{2}  \times  \sqrt{36}   \times  \sqrt{2} \times  \sqrt{5}

6\sqrt{2}  \times  \sqrt{2} \times  \sqrt{5}

Note that:

\sqrt{a}  \times  \sqrt{a}  = a

6\times 2 \sqrt{5}  = 12 \sqrt{5}

4 0
3 years ago
NO LINKS!!
dexar [7]

Answer: Anything between 0 and 10, excluding both endpoints.

In terms of symbols we can say 0 < w < 10 where w is the width.

===================================================

Explanation:

You could do this with two variables, but I think it's easier to instead use one variable only. This is because the length is dependent on what you pick for the width.

w = width

2w = twice the width

2w-5 = five less than twice the width = length

So,

  • width = w
  • length = 2w-5

which lead to

area = length*width

area = (2w-5)*w

area = 2w^2-5w

area < 150

2w^2 - 5w < 150

2w^2 - 5w - 150 < 0

To solve this inequality, we will solve the equation 2w^2-5w-150 = 0

Use the quadratic formula. Plug in a = 2, b = -5, c = -150

w = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\w = \frac{-(-5)\pm\sqrt{(-5)^2-4(2)(-150)}}{2(2)}\\\\w = \frac{5\pm\sqrt{1225}}{4}\\\\w = \frac{5\pm35}{4}\\\\w = \frac{5+35}{4} \ \text{ or } \ w = \frac{5-35}{4}\\\\w = \frac{40}{4} \ \text{ or } \ w = \frac{-30}{4}\\\\w = 10 \ \text{ or } \ w = -7.5\\\\

Ignore the negative solution as it makes no sense to have a negative width.

The only practical root is w = 10.

If w = 10 feet, then the area = 2w^2-5w results in 150 square feet.

----------------------

Based on that root, we need to try a sample value that is to the left of it.

Let's say we try w = 5.

2w^2 - 5w < 150

2*5^2 - 5*5 < 150

25 < 150 ... which is true

This shows that if 0 < w < 10, then 2w^2-5w < 150 is true.

Now try something to the right of 10. I'll pick w = 15

2w^2 - 5w < 150

2*15^2 - 5*15 < 150

375 < 150 ... which is false

It means w > 10 leads to 2w^2-5w < 150  being false.

Therefore w > 10 isn't allowed if we want 2w^2-5w < 150 to be true.

4 0
2 years ago
Parallelogram RSTU is shown.
mixas84 [53]

Answer:

-opposite sides of a parallelogram are congruent.

-definition of a parallelogram

- alternate interior angles are congruent

Step-by-step explanation:

I just did the test

5 0
3 years ago
Read 2 more answers
Bens shape covered 20 square centermiters what would be the shapes total area if another 10 square centermiters were added
Nookie1986 [14]
10+20 =30 so the answer is 30 square centimeters
5 0
3 years ago
Read 2 more answers
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