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REY [17]
3 years ago
13

2x+4(7−x) HELP PLEASE IM DEPERATEEEEE

Mathematics
2 answers:
jeka943 years ago
7 0
-2x+28


2x+4(7-x). Distribute the 4 to 7 and -x
2x+28-4x. Group the like terms
2x-4x+28. Simplify
-2x+28. Here’s your answer
goldenfox [79]3 years ago
4 0

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{ - 2x + 28}}}}}

Step-by-step explanation:

\sf{2x + 4(7 - x)}

Distribute 4 through the parentheses

\dashrightarrow{ \sf{2x + 28 - 4x}}

Collect like terms

\dashrightarrow{ \sf{2x - 4x + 28}}

\dashrightarrow{ \sf{ - 2x + 28}}

Hope I helped!

Best regards! :D

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Answer:

Step-by-step explanation:

Find the parabola through  ( 2 , − 3 )  with vertex  ( 1 , 2 ) .

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Download docx
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3 years ago
Which statement describes the solutions of this equation?
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2 years ago
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Let the universal set be the set of integers and let A = {x | x^2 ≤ 5}. Write A using the roster method.
Zarrin [17]

Answer:

Step-by-step explanation:

Given that Z the set of integers is the universal set and

A is given in set builder form.

A = {x | x^2 ≤ 5}

To convert this into roster form, we can find solutions for x

When x^2\leq 5\\|x|\leq \sqrt{5} =2.236

i.e. all integers lying between -2.236 and 2.236

The only integers satisfying this conditions are

-2,-1,0,1,2

Hence A in roster form is

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8 0
3 years ago
Define f(0,0) in a way that extends f to be continuous at the origin. f(x, y) = ln ( 19x^2 - x^2y^2 + 19 y^2/ x^2 + y^2) Let f (
kirill115 [55]

Answer:

f(0,0)=ln19

Step-by-step explanation:

f(x,y)=ln(\frac{19x^2-x^2y^2+19y^2}{x^2+y^2}) is given as continuous function, so there exist lim_{(x,y)\rightarrow(0,0)}f(x,y) and it is equal to f(0,0).

Put x=rcosA annd y=rsinA

f(r,A)=ln(\frac{19r^2cos^2A-r^2cos^2A*r^2sin^2A+19r^2sin^2A}{r^cos^2A+r^2sin^2A})=ln(\frac{19r^2(cos^2A+sin^2A)-r^4cos^2Asin^a}{r^2(cos^2A+sin^2A)})

we know that cos^2A+sin^2A=1, so we have that

f(r,A))=ln(\frac{19r^2-r^4cos^2Asin^a}{r^2})=ln(19-r^2cos^2Asin^2A)

lim_{(x,y)\rightarrow(0,0)}f(x,y)=lim_{r\rightarrow0}f(r,A)=ln19

So f(0,0)=ln19.

8 0
3 years ago
Solve by elimination 3×+11y=4,-2×-6y=0
gizmo_the_mogwai [7]
3x + 11y = 4

2x + 6y = 0

I got
15/2, -5/4
6 0
3 years ago
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