Answer:
y=20(6)^x
Step-by-step explanation:
hello :
the graph passes through the point (0,20) : when x=0 and y=20 :
20= ab^0 so a=20 because : b^0 = 1
the graph passes through the point (3,4320) : when x=3. and y=4320 : 4320= ab^3 but : a=20 so : 4320 = 20b^3
so : b^3 = 4320/20 = 216...... 216 = 6^3
b^3 = 6^3
b=6
the function is : y=20(6)^x
Answer:
y=-8/3x-11 is the equation of the line and the value of y
Step-by-step explanation:
Use point slope form m = y-y1/x-x1, or y-y1=m(x-x1)
Find the slope from the two points (-6,5) and (-3,-3)
m = y2-y1/x2-x1 = -3-5/-3+6 = -8/3
use one point say (-6,5) that passes through the line and the slope to form the equation y-5=-8/3(x+6) rearrange y= -8/3(x+6)+5
y=-8/3x - 48/3 +5 = -8/3x-16+5 = -8/3x-11
Answer: D. minimizes the sum of the squared residuals
Step-by-step explanation: The ordinary least square method is often used in locating the trendine which best fits a graphical linear model. The best is one in which the sum of the squared residual is smallest. The residual refers to the difference between the actual and the predicted points. The sum of the squared differences is obtained and the trend line is positioned where the residual is minimum. Choosing a OLS, and minimizing the sum.of the squared residual, the error difference between the predicted and actual score is minimized or reduced, hence, improving the prediction accuracy of our model.
Answer:
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Answer:
Given bivariate data, first determine which is the independent variable, x, and which is the dependent variable, y. Enter the data pairs into the regression calculator. Substitute the value for one variable into the equation for the regression line produced by the calculator, and then predict the value of the other variable.
Step-by-step explanation:
