Answer:
this is the formula for area of a trapezoid
Ax+by=c
y=x+3
subtract x from both sides
Y-x=x-x+3
Y-x=3
-1•(y-x)=-1•3
-y+x=-3
Reorder:
X-y=-3
I’m not sure if it’s 100% correct but that’s all I can do
A simple way to get the dimensions is just to rearrange the equation.
<span>So in a.) (i'm going to assume t2 is t squared) </span>
<span>rearrange: </span>
<span>x = Bt2 ----> B= x/t2 </span>
<span>Now you are told that x is displacement (L) and t is time (T) so sub these in. </span>
<span>B= L/T2 Therefore the dimensions are L/T2. </span>
<span>In b.) following the same steps: </span>
<span>x = A sin(2πft) ----> A = x/sin(2πft) </span>
<span>The hint tells you that sin(2πft) is dimensionless so you can disregard that part. </span>
<span>A = x </span>
<span>A=L</span>
K= 5
Step-by-step explanation:
You must count the distance between so if you look at where it lines up perfect -3,0 up to 2 the distance is 5