Question

If 98 is added to a number, the result is 36 less than three times the number. Find the number.

Answer 1

Answer:

$\tex\huge\boxed{67}$

Step-by-step explanation:

In order to solve this problem, we should set it up in an algebraic equation. Doing so will make it easier to make sense of the problem. To do this, we can represent each part of the statement with an expression.

For the purposes of this, let's call our unknown number $n$.

1. If 98 is added to a number = $n+98$
2. The result is, =
3. 36 less than 3 times the number = 3n - 36

Altogether, we get $n+98=3n-36$. We can now solve for $n$.

1. Remove the $\bold{n}$ term from one side. $n+98 - n = 3n -36 - n$
2. $98 = 2n-36$
3. Isolate the $\bold{n}$ term. $98+36=2n-36+36$
4. $134=2n$
5. Get $\bold{n}$ by itself. $134 \div 2 = 2n \div 2$
6. $67=n$

Therefore, the answer here is 67.

Hope this helped!