I need help..please..ASAP

AO = 5 AB = 12 Find x

viktelen [127]

Angle OAB is a right angle, since line AB is tangent to the circle at A. Thus, triangle AOB is a right triangle.

Applying the Pythagorean Theorem: 5^2 + 12^2 = |OB|^2

Then |OB|^2 = 13^2, and |OB| = 13.

We find x by subtracting |OC| from 13: 13 - 5 = 8.

Line segment has length 8; x = 8.

4 0

4 years ago

Suppose the man in the St. Ives poem has x wives, each wife has x sacks, each sack has x cats, and each cat has x kits. Write an

marishachu [46]

Answer: $x+x^2+x^3+x^4$

Step-by-step explanation:

As per given,

Number of wives = $x$

Number of sacks = $x (\text{Number of wives} )= x\times x = x^2$

Number of cats = $x(\text{Number of sack})$ $= x \times x^2=x^3$

Number of kits = $x(\text{Number of cats} )=x\times x^3=x^4$

Now , the total number of kits, cats, sacks, and wives going to St. Ives = $x+x^2+x^3+x^4$

Hence, the required ex[pression: $x+x^2+x^3+x^4$

5 0

3 years ago

Lines m and n are parallel lines cut by a transversal l.

Igoryamba

Answer:

Angles 1 and 3 are congruent as vertical angles; angles 3 and 7 are congruent as corresponding angles.

Step-by-step explanation:

<1 and <3 are vertical angles because they are formed by the same lines and are opposite each other . 3 and 7 are corresponding angles because they are in the same position at each intersection where a straight line crosses two others. Since the lines are parallel, they are equal That makes 1 and 7 equal

5 0

3 years ago

Read 2 more answers

Helppp meeeee pleaseeeee

Irina18 [472]

Answer:

1.) 4

2.) -11

3.) -4

4. 19

Step-by-step explanation:

5 0

3 years ago

The sensitivity is about 0.993. That is, if someone has HIV, there is a probability of 0.993 that they will test positive. • The

seraphim [82]

Answer:

(a) The probability that someone will test positive and have HIV is 0.000025.

(b) The probability that someone will test positive and not have HIV is 0.0001.

(c) The probability that someone will test positive is 0.000125.

(d) The probability a person has HIV given that he/she was tested positive is 0.1986.

Step-by-step explanation:

Denote the events as follows:

X = a person has HIV

Y = a person is tested positive for HIV.

The information provided is:

$P(Y|X)=0.993\\P(Y^{c}|X^{c})=0.9999\\P(X)=0.000025$

Compute the probability of a person not having HIV as follows:

$P(X^{c})=1-P(X)=1-0.000025=0.999975$

Compute the probability of $(Y^{c}|X)$ as follows:

$P(Y^{c}|X)=1-P(Y|X)=1-0.993=0.007$

Compute the probability of as $(Y|X^{c})$ follows:

$P(Y|X^{c})=1-P(Y^{c}|X^{c})=1-0.9999=0.0001$

(a)

Compute the probability that someone will test positive and have HIV as follows:

$P(Y\cap X)=P(Y|X)P(X)\\=0.993\times0.000025\\=0.000024825\\\approx0.000025$

Thus, the probability that someone will test positive and have HIV is 0.000025.

(b)

Compute the probability that someone will test positive and not have HIV as follows:

$P(Y\cap X^{c})=P(Y|X^{c})P(X^{c})\\=0.0001\times0.999975\\=0.0000999975\\\approx0.0001$

Thus, the probability that someone will test positive and not have HIV is 0.0001.

(c)

Compute the probability that someone will test positive as follows:

$P(Y)=P(Y\cap X)+P(Y\cap X^{c})=0.000025+0.0001=0.000125$

Thus, the probability that someone will test positive is 0.000125.

(d)

Compute the probability a person has HIV given that he/she was tested positive as follows:

$P(X|Y)=\frac{P(Y|X)P(X)}{P(Y)} \\=\frac{0.993\times0.000025}{0.000125}\\ =0.1986$

Thus, the probability a person has HIV given that he/she was tested positive is 0.1986.

As the probability of a person having HIV given that he was tested positive is not very large, it would not be wise to implement a random testing policy.

3 0

4 years ago