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kirill115 [55]
3 years ago
7

Given C(4, 3) and D(-4, -3) are two points on a circle, centered at the origin. Given

Mathematics
1 answer:
irinina [24]3 years ago
8 0

Answer:000

Step-by-step explanation:000

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What is the value of the expression below when z = 2?<br> 5z^2+3z+7
Marina CMI [18]

Answer: 33

5(2)² + 3(2) + 7

20 + 6 + 7

33

Hope this helps!

6 0
3 years ago
Can i get its answer?​
Komok [63]

Yo sup??

perimeter=2(l+b)

100=2(35+b)

b=15 cm

area=b*h

=35*15

=525 cm²

Hope this helps

4 0
3 years ago
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AngleFBC and AngleCBG are supplements, AngleDBG and AngleDBF are supplements, and AngleCBG Is-congruent-to AngleDBF. 4 lines are
aniked [119]

Answer:

b

Step-by-step explanation:

i just did it on edginity

5 0
3 years ago
D -e/3d + e= e, for d​
navik [9.2K]

Answer:

\large\boxed{d=\dfrac{e^2+e}{1-3e}}

Step-by-step explanation:

\dfrac{d-e}{3d+e}=e\\\\\dfrac{d-e}{3d+e}=\dfrac{e}{1}\qquad\text{cross multiply}\\\\(1)(d-e)=(e)(3d+e)\qquad\text{use the distributive property}\\\\d-e=3de+e^2\qquad\text{add}\ e\ \text{to both sides}\\\\d=3de+e+e^2\qquad\text{subtract}\ 3de\ \text{from both sides}\\\\d-3de=e^2+e\qquad\text{distribute}\\\\d(1-3e)=e^2+e\qquad\text{divide both sides by}\ (1-3e)\\\\d=\dfrac{e^2+e}{1-3e}

8 0
3 years ago
An art history professor assigns letter grades on a test according to the following scheme.A: Top 5% of scoresB: Scores below th
adoni [48]

Answer:

Grade B score:

76 \leq x \leq 89    

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 73.3

Standard Deviation, σ = 9.7

We are given that the distribution of score on test is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

B: Scores below the top 5% and above the bottom 62%

We have to find the value of x such that the probability is 0.62

P( X > x) = P( z > \displaystyle\frac{x - 73.3}{9.7})=0.62  

= 1 -P( z \leq \displaystyle\frac{x - 73.3}{9.7})=0.62  

=P( z \leq \displaystyle\frac{x - 73.3}{9.7})=0.38  

Calculation the value from standard normal z table, we have,  

\displaystyle\frac{x - 73.3}{9.7} = 0.305\\\\x = 76.26  

We have to find the value of x such that the probability is 0.05

P(X < 0.95) = \\\\P( X < x) = P( z < \displaystyle\frac{x - 73.3}{9.7})=0.95

Calculation the value from standard normal z table, we have,  

\displaystyle\frac{x - 73.3}{9.7} = 1.645\\\\x = 89.26  

Thus, the numerical value of score to achieve grade B is

76 \leq x \leq 89

7 0
3 years ago
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