If you're talking about Microsoft PowerPoint, just go to the slide view, right click and click "Duplicate Slide".
I'm sure you can also Copy and Paste slides.
Yes. The monitor is considered as a piece of Computer Hardware. Computer hardware is what you can physically touch, like the keyboard, mouse, monitor, disk drive, and so on.
I hope this answers your question.
Thank you,
Otaku
Answer:
Option d is the correct answer for the above question.
Explanation:
- The first loop of the program has a second loop and then the statement. In this scenario, the second loop executes for the value of the first loop and the statement executes for the value of the second loop.
- The first loop executes 4 times, Then the second loop or inner loop executes n times for the n iteration of the first loop, for example, 1 time for the first iteration of the first loop, 2 times for the second iteration of the first loop and so on.
- Then the inner loop executes (1+2+3+4) iteration which gives the result 10 iterations.
- The sum initial value is 0 and the "sum++", increase the value of the sum by 1.
- So the value of the sum becomes 10 after completing 10 iterations of the inner for loop.
- Hence the 10 will be the output. So the Option d is the correct answer while the other is not.
If Dominic is to design a network for Pirate Press he would have to consider and know of the following:
a. Growing capital - he needs to know if the company's sales is growing or is in debt so that he would know what course of action he could take in case he pursues projects for the company.
b. People/Team - the people/team working are the heart and soul of any company and knowing their specific needs and how they work is key to knowing how the company works as one unit
c. Marketing of the product - he needs to know how the product sells in order for him to decide what other strategies he can incorporate to make the product more marketable to people.
Answer:
<em>This program is written in C++</em>
<em>Comment are used to explain difficult lines</em>
<em>The first program that prints 0 to 20 (in decimal) starts here</em>
#include<iostream>
int main()
{
//Print From 0 to 20
for(int i = 0;i<21;i++)
{
std::cout<<i<<'\n';
}
}
<em>The modified program to print 0 to 20 in hexadecimal starts here</em>
#include<iostream>
using namespace std;
int main()
{
//Declare variables to use in conversion;
int tempvar, i=1,remain;
//Declare a char array of length 50 to hold result
char result[50];
//Print 0
cout<<"0"<<endl;
// Iterate from 1 to 20
for(int digit = 1; digit<21; digit++)
{
//Start Conversion Process
//Initialize tempvar to digit (1 to 20)
tempvar = digit;
while(tempvar!=0)
{
//Divide tempvar by 16 and get remainder
remain = tempvar%16;
if(remain<10)
{
result[i++]=remain + 48;
}
else
{
result[i++] = remain + 55;
}
//Get new value of tempvar by dividing it by 16
tempvar/=16;
}
//Print result
for(int l=i-1;l>0;l--)
{
cout<<result[l];
}
i=1;
cout<<endl;
}
return 0;
}
//The Program Ends Here
See Attachments for program 1 and 2; program 2 is the modified version of 1
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cpp
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