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Olenka [21]
2 years ago
10

PLZ HELP MEEEE!!

Mathematics
1 answer:
arsen [322]2 years ago
6 0

Answer:

42x+6y>24

Step-by-step explanation: im sorry if i am wrong but i belive that is correct

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Write the decimal 1.822 as a fraction. Do not write in lowest terms.
Degger [83]
Answer to your problem is:

1 411/500

I believe XD.
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Markers are sold in boxes, packs, or as single markets. Each box has 10 packs. Each pack has 10 markers. Draw a picture to show
Lapatulllka [165]
You could buy 276 single markers, you can buy 28 packs of markers, or 3 boxes of marker because 1pack = 10 markers, 10 markers multiplied by 10 packs equals 100. So 1 box would have 100 markers in it and if you took 2 boxes you would be missing 76 markers, so you're better off getting 3 boxes and having 300 markers than being less by 76.
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4 years ago
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Write an inequality for: There are at most 50 people on the bus.
Harman [31]

Answer:

>50

Step-by-step explanation:

It says there is at most 50 people so it'd be less than 50

7 0
3 years ago
Write the general equation for the circle that passes through the points (1, 1), (1, 3), and (9, 2).
Burka [1]

Step-by-step explanation:

As we know that

  • The circle center is equidistant from all three points, the distance being the circle radius.
  • Any point equidistant from two points must lie on the perpendicular bisector of the line segment which join those two points.
  • Which is, on the line through the midpoint of the line segment, perpendicular to the line segment.

The perpendicular bisector of the line segment joining the points (1, 1) and (1, 3) will be:

                   \:y=\:\frac{1+3}{2}=\frac{4}{2}=2

The perpendicular bisector of the line segment joining the points (1, 3), and (9, 2) will be:

                   x=\:\frac{1+9}{2}=\frac{10}{2}=5

These intersect at the center of the circle (5, 2).

The distance between (1, 1) and (5, 2) will be:

\mathrm{Compute\:the\:distance\:between\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\quad \sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}

\mathrm{The\:distance\:between\:}\left(1,\:1\right)\mathrm{\:and\:}\left(5,\:2\right)\mathrm{\:is\:}

=\sqrt{\left(5-1\right)^2+\left(2-1\right)^2}

=\sqrt{4^2+1}

=\sqrt{16+1}

=\sqrt{17}

So the equation of the circle can be written as:

\left(x-5\right)^2+\left(y-2\right)^2=17

x^2-10x+y^2+29-4y=17

x^2-10x+y^2-4y+12\:=0

x^2+y^2-10x-4y+12=0

8 0
3 years ago
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STALIN [3.7K]

Answer:

47 hours

Step-by-step explanation:

564/12 = 47

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3 years ago
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