On windows, it is the type command.
On linux, the cat command outputs the file.
All bytes that represent printable characters will be displayed as ASCII or even Unicode.
Answer:
Explanation:
The Hexa-decimal numbers have base 16 and includes numbers:
0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E and F
The given steps are performed to convert a decimal number to hexa-decimal number, here to convert decimal number 35 to hexa-decimal number:
- Divide 35 by 16
- Note the remainder, r which is 3 here and quotient which is 2
- Again divide 2 (quotient) by 16 and note the remainder, r' which is 2 and quotient is 0
- We will stop here as the quotient is now 0. Usually division by 16 is repeated until we get quotient = 0
- Now arrange the remainder in reverse order to get the hexa-decimal number as r'r
- The hexa-decimal number is
Answer:
The program is written using PYTHON SCRIPT below;
N=int(input(" Enter number of Rows you want:"))
M=[] # this for storing the matrix
for i in range(N):
l=list(map(int,input("Enter the "+str(i+1)+" Row :").split()))
M.append(l)
print("The 2D Matrix is:\n")
for i in range(N):
print(end="\t")
print(M[i])
W=[] # to store the first non zero elemnt index
T=[] # to store that value is positive or negative
L=len(M[0])
for i in range(N):
for j in range(L):
if (M[i][j]==0):
continue
else:
W.append(j) # If the value is non zero append that postion to position list(W)
if(M[i][j]>0): #For checking it is positive or negative
T.append(+1)
else:
T.append(-1)
break
print()
print("The first Non Zero element List [W] : ",end="")
print(W)
print("Positive or Negative List [T] : ",end="")
print(T)
Explanation:
In order for the program to determine a set of test cases it takes in input of 2D matrix in an N numbet of rows.
It goes ahead to program and find the column index of the first non-zero value for each row in the matrix A, and also determines if that non-zero value is positive or negative. The If - Else conditions are met accordingly in running the program.
Answer:
how many event you have been too in the last month (well non during this time but as an example)
Explanation:
Answer:
scoop1 - 10
Explanation:
If we want scoop2 to be 10 pixels less than scoop1, we can simply subtract 10 from scoop1 to get the needed value from scoop2.
