brainly.com/question/10887381
Answer:You need 7 bits to encode everything that could be typed on this keyboard.
Explanation:
The encoding of the QWERTY keyboard is based on the extended ASCII encoding. The "ASCII" code was created by the "American standards association" in 1963.The acronym of “American Standard Code for Information Interchange” is ASCII. ASCII is a 7-bit code.
Further Explanation:
The QWERTY keyboard is the standard computer and typewriter keyboard design for Latin-script alphabets. The first six letters of the keyboard's upper row indicate its name. Christopher Latham Sholes designed the layout of the keyboard for his "Type-Writer". It was first mass-produced in 1874.
In QWERTY keyboard, extended American Standard for Information Interchange (ASCII) method is used for characters encoding. Alphabetical order of English language is the base of ASCII method of characters encoding.
Learn More:
Learn more about QWERTY keyboard: brainly.com/question/649081; Answered by: Jessusulas
Learn more about ASCII: brainly.com/question/7851735; Answered by: LearnGrow
Keywords:
QWERTY keyboard, The encoding of the QWERTY keyboard, American Standard for Information Interchange, ASCII
Answer:
The applicatiion and its program output are given below
Explanation:
start
declaration:
int numberOfMember,totalNumber,j=0
string array05[totalNumber],array612[totalNumber],array1320[totalNumber],arrayMore20[totalNumber]
string trainerName;
Loop start:
for i=0-totalNumber
totalNumber=number of trainers
trainerName=name of trainer
numberOfMember=number of memberas added
if numberOfMember=0-5
array05[j]=trainerName;
elseif numberOfMember=6-12
array612[j]=trainerName;
elseif numberOfMember=13-20
array1320[j]=trainerName;
else
arrayMore20[j]=trainerName;
j+=1;
end loop
Output:
for i=0-j
print array05[i] array612[i] array1320[i] arrayMore20[i]
End
Answer:
i= 1
for i in range(1,n):
if i * i < n:
print(2* i + 1)
i += 1
else:
print('Hakuna Matata')
Explanation:
First, there's a need to rewrite the code segment in your question (because of indentation)
<em>i= 1</em>
<em>while i*i < n:</em>
<em> print(2* i + 1)</em>
<em> i += 1</em>
<em>else:</em>
<em> print('Hakuna Matata')</em>
<em />
The explanation of the equivalent of the above while loop is as follows
This line initializes i to 1
i= 1
This line iterates from 1 to n-1
for i in range(1,n):
This line checks if i * i is less than n
if i * i < n:
The following line is executed if the above condition is satisfied; otherwise, nothing is done
print(2* i + 1)
The value of i is incremented by 1 using this line
i += 1
The following is executed at the end of the iteration
else:
print('Hakuna Matata')
<em>Note: Assume any value of n, both programs display the same output</em>
According to my opinion,
NO, I'd not feel comfortable.
Substitution ciphers in the world of encryption can be
cracked very easily. By looking for patterns like one letter words, double
letter patterns, and knowing rules such as all words must contain at least an
a, e, i, o, u or y, you are probably able to decipher this with so much ease. While
this information and the frequency of letters used in the encrypted message might
be helpful, it might not be a perfect process.
