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Tom [10]
1 year ago
13

A segment in the complex plane has a midpoint at 3 – 2i. If one endpoint of the segment is at 7 i, what is the other endpoint? –

1 – 5i 5 – 0. 5i 10 – i 11 4i.
Mathematics
1 answer:
Brut [27]1 year ago
6 0

The midpoint of a segment divides the segment into equal halves

The other endpoint is 1- 5i

<h3>How to determine the missing endpoint </h3>

The coordinates are given as:

Point 1: 7 + i

Midpoint: 3 - 2i

Represent the other endpoint with x.

So, we have:

2 * Midpoint = Point 1 + x

This gives

2 * (3 - 2i) =7 + i + x

6 - 4i =7 + i + x

Collect like terms

x = 6 -7- 4i -i

Evaluate the like terms

x = 1- 5i

Hence, the other endpoint is 1- 5i

Read more about midpoints ta:

brainly.com/question/9635025

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D is the answer most  likely your answer

Step-by-step explanation:

3.14x81x6=1526.04 which rounding would be 1526cm^3

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2 years ago
Emily has a road map with a key that shows an inch on the map equals 5 miles of actual distance.if a distance measured on the ma
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12 * 5 is 60.
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3 years ago
What is 4.5(-20)+18=
Vikki [24]

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-72

Step-by-step explanation:

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2 years ago
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20 points if you help me solved this problem plz it’s urgent someone plz help me I need help! Will mark you as brainiest!
deff fn [24]

Answer:  see below

<u>Step-by-step explanation:</u>

C(x) = 39 when 0 < x ≤ 1.0

C(x) = 63 when 1.0 < x ≤ 2.0

C(x) = 87 when 2.0 < x ≤ 3.0

C(x) = 111 when 3.0 < x ≤ 4.0

C(x) = 135 when 4.0 < x ≤ 5.0

C(x) = 159 when 5.0 < x ≤ 6.0

Based on the information I provided above, the answers are:

a) x= 0.6, C(x) = 1.0

   x = 1.0, C(x) = 39

   x = 1.1,  C(x) = 63

   x = 2.5, C(x) = 87

   x = 3.0, C(x) = 87

   x = 4.8, C(x) = 135

   x = 5.0, C(x) = 135

   x = 5.3, C(x) = 159

b) If C(x) = 87, then 2.0 < x ≤ 3.0

c) Domain (all possible x-values): 0 < x ≤ 6.0

d) Range (all possible y-values): {39, 63, 87, 111, 135, 159}

3 0
3 years ago
Find the 5th term of the sequence in which T1=8 and Tn=3t n-1
yan [13]
T_n = 3 * T_(n-1)

Long way (always works!)
T_5 = 3*T_4,
T_4 = 3*T_3
T_3 = 3*T_2
T_2 = 3*T_1

T_5 = 3*3*3*3*T_1 = 81*T_1 = 81*8 = 648!

Short way (sometimes it works!)

T_n = 3^(n-1) * T_1 (this case is a geometric series of ratio-=3)
T_5 = 3^4*8 = 648
6 0
2 years ago
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