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Tom [10]
2 years ago
13

A segment in the complex plane has a midpoint at 3 – 2i. If one endpoint of the segment is at 7 i, what is the other endpoint? –

1 – 5i 5 – 0. 5i 10 – i 11 4i.
Mathematics
1 answer:
Brut [27]2 years ago
6 0

The midpoint of a segment divides the segment into equal halves

The other endpoint is 1- 5i

<h3>How to determine the missing endpoint </h3>

The coordinates are given as:

Point 1: 7 + i

Midpoint: 3 - 2i

Represent the other endpoint with x.

So, we have:

2 * Midpoint = Point 1 + x

This gives

2 * (3 - 2i) =7 + i + x

6 - 4i =7 + i + x

Collect like terms

x = 6 -7- 4i -i

Evaluate the like terms

x = 1- 5i

Hence, the other endpoint is 1- 5i

Read more about midpoints ta:

brainly.com/question/9635025

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Answer:

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Step-by-step explanation:

Now,

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5 0
3 years ago
In a manufactory, there are two types of spoilages. It is found that 5% of spoilages are due to transformer spoilage, 8% are due
jok3333 [9.3K]

Answer:

   

Step-by-step explanation:

Let us denote probability of   spoilage as follows

Transformer spoilage = P( T ) ; line spoilage P ( L )

Both P ( T ∩ L ) .

Given

P( T )  = .05

P ( L ) = .08

P ( T ∩ L ) = .03

a )

For independent events

P ( T ∩ L ) =  P( T ) x  P ( L )

But  .03  ≠  .05 x .08

So they are not independent of each other .

b )

i )

Probability of line spoilage given that there is transformer spoilage

P L/ T ) = P ( T ∩ L ) / P( T )

= .03 / .05

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ii )

Probability of transformer spoilage but not line spoilage.

P( T ) - P ( T ∩ L )

.05 - .03

= .02

iii )Probability of transformer spoilage given that there is no line spoilage

[ P( T ) - P ( T ∩ L ) ] / 1 - P ( L )

=  .02 / 1 - .08

= .02  / .92

= 1 / 49.

i v )

Neither transformer spoilage nor there is no line spoilage

= 1 - P ( T ∪ L )

1 - [  P( T ) +  P ( L ) - P ( T ∩ L ]

= 1 - ( .05 + .08 - .03 )

=  0 .9

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Step-by-step explanation:

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tan 66 = BC/ 5

Multiply each side by 5

5 tan 66 = BC

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Rounding to the nearest tenth

11.2 = BC

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