Answer:
A closed cone has 0 verticals.. but 1 vertice
Step-by-step explanation:
x^2 + 7x + 3 in^2.
The area of the whole frame = (5x + 3)(x + 6)
= 5x^2 + 33x + 18
So the area of the rim = 5x^2 + 33x + 18 - (4x^2 + 26x + 15)
= x^2 + 7x + 3 in^2.
25 in²
A = hb = × 5 × 10 = 25 in²
