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nirvana33 [79]
2 years ago
10

Please Evaluate this equation

Mathematics
2 answers:
alexira [117]2 years ago
8 0

Answer:

Step-by-step explanation:

1.169

Evgesh-ka [11]2 years ago
4 0

Answer:

8^2−38+85+3√8 =111+6√2

(Decimal: 119.485281)

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May I get some help with this, please?!? I will greatly appreciate it!
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Answer:

its C

Step-by-step explanation:

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You are working on an urban planning project assessing the growth of a city. Five years ago, the population was 134,785 The curr
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To calculate growth rate, start by subtracting the past value from the current value. Then, divide that number by the past value. Finally, multiply your answer by 100 to express it as a percentage.

<u>Explanation:</u>

The "population growth rate" is the rate at which the number of individuals in a population increases in a given time period, expressed as a fraction of the initial population. Population growth is based on four fundamental factors: birth rate, death rate, immigration, and emigration.

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3 years ago
If i can get 3 snapple Iced tea. and its 3 for $6 How would it be if i get 2 snapple Iced tea?
nikklg [1K]

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4 dollars for 2 drinks (2 dollars for 1 drink)

Step-by-step explanation:

Okay, so you can get 3 snapple drinks from 6 dollars. and you want to know the cost of 2 snapple drinks.

3 ÷ 6 = 2

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Marco's polo team has a budget for new uniforms of $250. If there are 12 members of the team, what can Marco spend on uniforms.
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7 0
3 years ago
f the price charged for a candy bar is​ p(x) cents, where p (x )equals 162 minus StartFraction x Over 10 EndFraction ​, then x t
andreev551 [17]

Answer:

a. 1620-x^2

b. x=810

c. Maximum value revenue=$656,100

Step-by-step explanation:

(a) Total revenue from sale of x thousand candy bars

P(x)=162 - x/10

Price of a candy bar=p(x)/100 in dollars

1000 candy bars will be sold for

=1000×p(x)/100

=10*p(x)

x thousand candy bars will be

Revenue=price × quantity

=10p(x)*x

=10(162-x/10) * x

=10( 1620-x/10) * x

=1620-x * x

=1620x-x^2

R(x)=1620x-x^2

(b) Value of x that leads to maximum revenue

R(x)=1620x-x^2

R'(x)=1620-2x

If R'(x)=0

Then,

1620-2x=0

1620=2x

Divide both sides by 2

810=x

x=810

(C) find the maximum revenue

R(x)=1620x-x^2

R(810)=1620x-x^2

=1620(810)-810^2

=1,312,200-656,100

=$656,100

7 0
4 years ago
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