Find the 7th term of the geometric sequence whose common ratio is 2/3 and whose first term is 4

Mathematics

1 answer:

BARSIC [14]1 year ago

8 0

Answer:

$a_{7}=\frac{256}{729}$ or $a_{7}=0.35$

Step-by-step explanation:

$a_{n} =a_{1}* r^{n-1}$

$a_{7}=4*\frac{2}{3}^{7-1}$

$a_{7}=4*\frac{2}{3}^{6}$

$a_{7}=4*\frac{64}{729}$

$a_{7}=\frac{256}{729}$

$a_{7}=0.35$

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Answer:

The margin of error for the 95% confidence interval for the mean score of all such subjects is of 8.45.

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

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