Question

Find the 7th term of the geometric sequence whose common ratio is 2/3 and whose first term is 4

Answer 1

Answer:

$a_{7}=\frac{256}{729}$   or   $a_{7}=0.35$

Step-by-step explanation:

$a_{n} =a_{1}* r^{n-1}$

$a_{7}=4*\frac{2}{3}^{7-1}$

$a_{7}=4*\frac{2}{3}^{6}$

$a_{7}=4*\frac{64}{729}$

$a_{7}=\frac{256}{729}$

or

$a_{7}=0.35$