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Mars2501 [29]
2 years ago
6

Complete the square and graph: 9y²−x − 18y +10=0 ​

Mathematics
2 answers:
Nitella [24]2 years ago
4 0

Answer:

See below ~

Step-by-step explanation:

Completing the square :

  • 9y² - x - 18y + 10 = 0
  • 9y² - 18y + 9 - 9 - x + 10 = 0
  • <u>(3y - 3)² - x + 1 = 0</u>

<u></u>

Graph :

KatRina [158]2 years ago
4 0

Answer:

x = 9(y - 1)² + 1

see attached for graph

Step-by-step explanation:

<h3><u>Completing the square</u></h3>

Given equation:

9y² - x - 18y + 10 = 0 ​

As there is a y² in the equation, this implies it is a <u>sideways parabola</u>.

To complete the square for a sideways parabola, collect the y variable terms on the left and everything else on the right:

⇒ 9y² - 18y = x - 10

Factor out the leading coefficient from the left side:

⇒ 9(y² - 2y) = x - 10

Take the coefficient of y, half it, then square it:  (-2 ÷ 2)² = 1

Add this inside the parentheses, and add the distributed value of this to the right side:

⇒ 9(y² - 2y + 1) = x - 10 + 9

Factor the parentheses and simplify the right side:

⇒ 9(y - 1)² = x - 1

Add 1 to both sides to make x the subject:

⇒ x = 9(y - 1)² + 1

<h3><u>Graphing the parabola</u></h3>

Conic form of a sideways parabola with a horizontal axis of symmetry:

x = a(y - k)² + h

(where (h, k) is the vertex and y = k is the axis of symmetry)

If a > 0, the parabola opens to the right, and if a < 0, the parabola opens to the left.

Therefore, for  x = 9(y - 1)² + 1

  • vertex = (1, 1)
  • axis of symmetry:  y = 1
  • a > 0 ⇒ the parabola opens to the right

To find the x-intercept, set y = 0 and solve for x:

⇒ x = 9(0 - 1)² + 1

⇒ x = 9(-1)² + 1

⇒ x = 9(1) + 1

⇒ x = 10

Therefore, the y-intercept is (10, 0)

As the axis of symmetry is y = 1, the other value of y when x = 10 is y = 2

Plot the vertex and points. Add an axis of symmetry to help draw the curve.  Draw the parabola opening to the right.

**graph attached**

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