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exis [7]
1 year ago
15

In an arithmetic sequence, if you are given a3=93 and a5=135, find a=100. Must show work to receive full credit.

Mathematics
1 answer:
Elanso [62]1 year ago
5 0

The 100th term of the sequence is 2130.

<h3>How to calculate the value?</h3>

a3 = a + 2d = 93

a5 = a + 4d = 135

Compute both equations

(4d - 2d) = (135 - 93)

2d = 42

d = 42/2 = 21

a + 2d = 93

a + 2(21) = 93

a + 42 = 93

a = 94 - 42 = 51

100th term will be:

= a + 99d

= 51 + 99(21)

= 51 + 2079

= 2130

Learn more about sequence on:

brainly.com/question/6561461

#SPJ1

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A particular brand of gasoline has a density of 0.737 g/ml at 25 ∘c. how many grams of this gasoline would fill a 13.4 gal tank
ruslelena [56]

Given, the density of a particular brand of gasoline = 0.737 g/ml.

13.4 gallon of tank given. We have to find the mass of gasoline to fill the tank.

First we will convert 13.4 gallon to ml.

We know that 1 gallon = 3.78541 litre

And 1 litre = 1000 ml

So we can write 1 gallon = (3.78541)(1000) ml = 3785.41 ml.

13.4 gallon = (3785.41)(13.4) ml = 50724.494 ml.

Let's take there is x grams of gasoline

We know that density = (mass/ volume) = \frac{x}{50724.494}

So we can write,

0.737 =\frac{x}{50724.494}

To find x we will multiply both sides by 50724.494. we will get,

(0.737)(50724.494) =(\frac{x}{50724.494}) (50724.494)

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So we have got the required answer.

Mass of gasoline = 37383.95 grams.

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