When
, we have


and of course 3 | 6. ("3 divides 6", in case the notation is unfamiliar.)
Suppose this is true for
, that

Now for
, we have

so we know the left side is at least divisible by
by our assumption.
It remains to show that

which is easily done with Fermat's little theorem. It says

where
is prime and
is any integer. Then for any positive integer
,

Furthermore,

which goes all the way down to

So, we find that

QED
The slope of the line with the points (2,-5) and (-6,5) is 5/-4 (or 10/-8).
The answer is
C = 4 ÷ 1/5
Let's separate this absolute value equation into two different equations.
x + 1 = 3.
Subtract 1 from each side
x = 2.
x + 1 = -3
Subtract 1 from each side
x = -4
The two solutions are x = 2 and x = -4
Answer:
Is there a diagram to this question?
Step-by-step explanation: