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3 years ago

Use properties or mental math to solve 5x395

Mathematics

1 answer:

shepuryov [24]3 years ago

3 0

Answer:

I got 1,475

Step-by-step explanation:

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7. Write the equation of a line which passes through the points (-3,5) and (6,23)

faust18 [17]

Answer:

answer to the equation is

$y = 2x + 11$

Step-by-step explanation:

$y = mx + b$

first find the slope of the line using the two points

$slope \: m = \frac{y2 - y1}{x2 - x1} = \frac{23 - 5}{6 - ( - 3)} \\ = \frac{18}{9} \\ slope \: m = 2$

substitute 2 for m and use one of the points for x and y and solve for b

$5 = 2( - 3) + b \\ 5 = - 6 + b \\ 5 + 6 = b \\ b = 11$

Now that you found b, the y-intercept, you can substitute that into the equation for your line

$y = 2x + 11$

7 0

3 years ago

What is the solution to the following system of linear equations?

Arturiano [62]

Answer:

i think it's B, no solutions

Step-by-step explanation:

because they are parallel to each other

3 0

3 years ago

Read 2 more answers

Find the longer leg of the triangle.

Paha777 [63]

Answer:

Choice A. 3.

Step-by-step explanation:

The triangle in question is a right triangle.

The length of the hypotenuse (the side opposite to the right angle) is given.
The measure of one of the acute angle is also given.

As a result, the length of both legs can be found directly using the sine function and the cosine function.

Let $\text{Opposite}$ denotes the length of the side opposite to the $30^{\circ}$ acute angle, and $\text{Adjacent}$ be the length of the side next to this $30^{\circ}$ acute angle.

$\displaystyle \begin{aligned}\text{Opposite} &= \text{Hypotenuse} \times \sin{30^{\circ}}\\ &=2\sqrt{3}\times \frac{1}{2} \\&= \sqrt{3}\end{aligned}$ .

Similarly,

$\displaystyle \begin{aligned}\text{Adjacent} &= \text{Hypotenuse} \times \cos{30^{\circ}}\\ &=2\sqrt{3}\times \frac{\sqrt{3}}{2} \\&= 3\end{aligned}$ .

The longer leg in this case is the one adjacent to the $30^{\circ}$ acute angle. The answer will be $3$ .

There's a shortcut to the answer. Notice that $\sin{30^{\circ}} < \cos{30^{\circ}}$ . The cosine of an acute angle is directly related to the adjacent leg. In other words, the leg adjacent to the $30^{\circ}$ angle will be the longer leg. There will be no need to find the length of the opposite leg.