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Dominik [7]
2 years ago
7

Can anyone help without using reciprocal?

Mathematics
1 answer:
vova2212 [387]2 years ago
3 0

Answer:

x = -5/3

Step-by-step explanation:

-4 = \dfrac{20}{3}x

-4×3 = 20 x

-12 = 20 x

x = \dfrac{-5}{3}

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Mary Grace has 3 more Jolly Ranchers than Isabella. If Isabella has 10 Jolly Ranchers, how many do they have total?
PilotLPTM [1.2K]

Answer:23

Step-by-step explanation:

10+3=13 so that means that mary has 13 and isabella has 10

Then if you add 13+10=23

so they have 23 jolly ranchers in all.

5 0
3 years ago
Read 2 more answers
Create an equivalent system of equations using the sum of the system and the first equation. x + 4y = 8 4x + y = 2
qaws [65]

Answer:

Equivalent systems of equations review

Step-by-step explanation:

We're given two systems of equations and asked if they're equivalent.

x + 4y = 8 (1)

4x + y = 2 (2)

Interestingly, if we sum the equations in System A, we get:

x + 4y = 8 \\4x + y = 2 \\

5x+5y=10

Replacing the first equation in System A with this new equation, we get a system that's equivalent to System A:

5x+5y=10

4x + y = 2

This is System B, which means that System A is equivalent to System B.

5 0
3 years ago
(2/5) + ( -1/4). Show your work by using the “butterfly” method.
pashok25 [27]

Answer:

0.15

Step-by-step explanation:

Step 1: Make sure the bottom numbers (the denominators) are the same

Step 2: Add the top numbers (the numerators), put that answer over the denominator

Step 3: Simplify the fraction (if needed)

3 0
2 years ago
If you add up all the numbers on a 1-10 ten-sided dice, you get 55. What’ the sum of all sides in a 20 dice?
OleMash [197]
If you add up all the numbers on a 1-10 ten-sided dice, you get 55. The sum of all sides on a 20-sided dice is 210.
6 0
3 years ago
I really am bad with math and just have given up
Slav-nsk [51]
Well hmmm does the graph open upwards or downwards?  well
is a quadratic, if the leading term's coefficient is negative, Down, if positive, Up

a)
now, let's see the leading term, -x², what's its coefficient? is -1 * x² or -1x², is -1, so is negative, thus is opening downwards

c)
x-intercepts occur, when y = 0, namely y = -x²-4x-3, so setting y to 0
0 = -x² -4x -3 take a common factor of -1, thus

0 = -1 (x²+4x+3)  <--- now, if we factor that out, notice, surely you've done many of these by now, so we end up with 

\bf \begin{array}{lcclll}&#10;0=x^2&+4x&+3\\&#10;&\uparrow &\uparrow \\&#10;&3+1&3\cdot 1&#10;\end{array}\\\\&#10;-----------------------------\\\\&#10;0=(x+3)(x+1)\implies &#10;\begin{cases}&#10;0=x+3\implies &-3=x\\&#10;0=x+1\implies &-1=x&#10;\end{cases}

so, the x-intercepts are at -3 and -1

d)

now, the y-intercepts, just set x = 0
y = -x²-4x-3, settting x to 0 y = -0²-4(0)-3, which is y = -3

so the sole y-intercept is at y = -3


now, let's get on to b)

b)   \bf \textit{vertex of a parabola}\\\\&#10;&#10;\begin{array}{lccclll}&#10;f(x)=&-1x^2&-4x&-3\\&#10;&\uparrow &\uparrow &\uparrow \\&#10;&a&b&c&#10;\end{array}\qquad &#10;\left(-\cfrac{{{ b}}}{2{{ a}}}\quad ,\quad  {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}\right)

and those are the coordinates, notice a = -1, b = -4 and c = -3

now, for

e)

well, all you have to do is, once you have the vertex, pick an x-value on the left-hand-side of the vertex, get they value for "y", or OUTPUT,

then pick another x-value, on the right-hand-side of the vertex, get the "y" value again, and plot away
7 0
3 years ago
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