Answer:
p(on schedule) ≈ 0.7755
Step-by-step explanation:
A suitable probability calculator can show you this answer.
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The z-values corresponding to the build time limits are ...
z = (37.5 -45)/6.75 ≈ -1.1111
z = (54 -45)/6.75 ≈ 1.3333
You can look these up in a suitable CDF table and find the difference between the values you find. That will be about ...
0.90879 -0.13326 = 0.77553
The probability assembly will stay on schedule is about 78%.
Answer:
f(x)=x^2
Step-by-step explanation:
Because it is a quadratic function this is the quadratic parent function.
Answer:
and let's then do away with the denominators, by multiplying both sides by the LCD of all fractions, in this case, the LCD will be 8, and then we'll combine the like-terms, but anyway, let's proceed.
Step-by-step explanation:
Answer:
$6261.61
Step-by-step explanation:
The solution to the differential equation is the exponential function ...
A(t) = 5000e^(0.0225t)
We want the account value after 10 years:
A(10) = 5000e^(0.225) = 6261.61
The value of the account after 10 years will be $6,261.61.
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The rate of change equation basically tells you that interest is compounded continuously. After working interest problems for a while you know the formula for that is the exponential formula A = A0·e^(rt).
Or, you can solve the differential equation using separation of variables:
dA/A = 0.0225dt
ln(A) = 0.0225t +C . . . . integrate
A(t) = A0·e^(0.0225t) = 5000·e^(0.0225t) . . . . solution for A(0) = 5000
Answer:
= 5
Step-by-step explanation:
z - x + y
4 - 2 + 3 = 5
