(3n + 1)(n-5)
Hope this helped
Answer:
Yes a^2mn
Step-by-step explanation:
You do this by multiplication.
Answer:
The average value of the function on the given interval 6.5.
Step-by-step explanation:
Consider the given function is

We need to find the average value of the function on the given interval [1,13].


The average value of the function f(x) on [a,b] is

Average value of the function on the given interval [1,13] is

![Average=\dfrac{1}{12}[\dfrac{x^2}{2}-0.5x]^{13}_{1}](https://tex.z-dn.net/?f=Average%3D%5Cdfrac%7B1%7D%7B12%7D%5B%5Cdfrac%7Bx%5E2%7D%7B2%7D-0.5x%5D%5E%7B13%7D_%7B1%7D)
![Average=\dfrac{1}{12}[\dfrac{(13)^2}{2}-0.5(13)-(\dfrac{(1)^2}{2}-0.5(1))]](https://tex.z-dn.net/?f=Average%3D%5Cdfrac%7B1%7D%7B12%7D%5B%5Cdfrac%7B%2813%29%5E2%7D%7B2%7D-0.5%2813%29-%28%5Cdfrac%7B%281%29%5E2%7D%7B2%7D-0.5%281%29%29%5D)
![Average=\dfrac{1}{12}[78-0]](https://tex.z-dn.net/?f=Average%3D%5Cdfrac%7B1%7D%7B12%7D%5B78-0%5D)

Therefore, the average value of the function on the given interval 6.5.
Answer:
Step by step explanation
I believe the answer is:
2b x (b-3) x (b+3)