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2 years ago

A population of bacteria is increasing by 10% cach hour. Find the percentage increase in the population every 3 hours.

Mathematics

1 answer:

Otrada [13]2 years ago

3 0

In 3 hours, it increases 33.1% .

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A groundskeeper needs grass seed to cover a circular field 380 feet in diameter A store sells 70 pound bags of grass seed. One p

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3 years ago

Read 2 more answers

Help please I needed!!!!

faust18 [17]

Answer:

Step-by-step explanation:

4. f(x) = √(x + 4)

f(5) = √(5+4) = √(9) = 3

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3 years ago

An isosceles triangle ABC has legs of length 24 and a vertex angle that measures 36º . Determine the length of its base, BC , to

iris [78.8K]

Answer: $BC=14.8$

Step-by-step explanation:

By definition, an Isosceles triangle has two equal sides and its opposite angles are congruent.

Observe the figure attached, where the isosceles triangle is divided into two equal right triangles.

So, in this case you need to use the following Trigonometric Identity:

$sin\alpha =\frac{opposite}{hypotenuse}$

In this case, you can identify that:

$\alpha =\angle BAD=\angle CAD=18\°\\\\opposite=BD=CD=x\\\\hypotenuse=AB=AC=24$

Substituting values, and solving for "x", you get:

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Therefore, the length of BC rounded to nearest tenth, is:

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3 years ago

The difference of two trinomials is x2 − 10x + 2. If one of the trinomials is 3x2 − 11x − 4, then which expression could be the

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Answer:

$4x^2-21x-2$

Step-by-step explanation:

Given that:

Difference of two trinomials is $x^2 - 10x + 2$

One of the two trinomials is $3x^2 - 11x - 4$

To find:

The other trinomial = ?

Four options are:

$2x2 - x - 2 \\2x2 + x + 6 \\4x2 + 21x + 6\\ 4x2 - 21x - 2$

Solution:

Let the two trinomials be A and B.

Given A - B = $x^2 - 10x + 2$

B = $3x^2 - 11x - 4$

We have to find the other trinomial A.

A - B = $x^2 - 10x + 2$

A - ( $3x^2 - 11x - 4$ ) = $x^2 - 10x + 2$

$\Rightarrow$ A = $x^2 - 10x + 2$ + ( $3x^2 - 11x - 4$ )

$\Rightarrow$ A = $4x^2-21x-2$

So, the correct answer is $4x^2-21x-2$ .

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3 years ago

A population of bacteria is increasing by 10% cach hour. Find the percentage increase in the population every 3 hours.​

A population of bacteria is increasing by 10% cach hour. Find the percentage increase in the population every 3 hours.