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Vlad1618 [11]
1 year ago
12

HELP I DONT UNDERSTAND! SOMEONE EXPLAIN

Mathematics
1 answer:
aleksandr82 [10.1K]1 year ago
3 0

Answer:

C

Step-by-step explanation:

if ethan jogged 13/3 of a mile (i converted it to an improper fraction) and chloe jogged 1 1/4 as much, thats basically just saying the same as ethan so 13/3, with an additional 1/4 of the distance ethan ran. so it would be 13/3+ 13/12, which is equal to 52/12+13/12, which is 65/12 unsimplified and 5 5/12 simplified

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Find the solutions to the equation below 30x^2-28x+6 =0
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For this case, we have the following equation of the second degree:

30x ^ 2-28x + 6 = 0

If we divide between 2 on both sides of the equation, we will have:

15x ^ 2-14x + 3 = 0

Where:

a = 15\\b = -14\\c = 3

The solutions will come from:

x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2 (a)}

Substituting:

x = \frac {- (- 14) \pm \sqrt {(- 14) ^ 2-4 (15) (3)}} {2 (15)}\\x = \frac {14 \pm \sqrt {196-180}} {30}\\x = \frac {14 \pm \sqrt {16}} {30}\\x = \frac {14 \pm4} {30}

So, we have:

x_ {1} = \frac{14 + 4} {30} = \frac {18} {30} = \frac {18} {30} = \frac {3} {5}\\x_ {2} = \frac {14-4} {30} = \frac {10} {30} = \frac {1} {3}\\

Answer:

x_ {1} = \frac {3} {5}\\x_ {2} = \frac {1} {3}

Option A

Option E

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Step-by-step explanation:

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Weight of Narwhal = 2\times10^3\text{ pounds}

Number of times blue whale's weight  is heavier than the narwhal's weight = =\dfrac{\text{Weight of Blue whale}}{\text{Weight of Narwhal }}

=\dfrac{3\times10^5}{2\times10^3}\\\\=1.5\times10^{5-3}\ \ \ [\dfrac{a^m}{a^n}=a^{m-n}]\\\\=1.5\times10^2\\\\=1.5\times100=150

Hence, the blue whale's weight is 150 times heavier than the narwhal's weight.

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