Ask question

Ask question

All categories

3 years ago

8

Please help , ayudame Por favor

1 answer:

Mumz [18]3 years ago

6 0

Answer:

Line segment AD

$AD = \sqrt{(c-0)^{2}+(d-0)^{2}}$

$AD = \sqrt{c^{2}+d^{2}}$

Line segment BC

$BC = \sqrt{[(b+c)-b]^{2}+(d-0)^{2}}$

$BC = \sqrt{c^{2}+d^{2}}$

Line segment AB

$AB = \sqrt{(b-0)^{2}+(0-0)^{2}}$

$AB = \sqrt{b^{2}+0^{2}}$

$AB = b$

Line segment CD

$CD = \sqrt{[c-(b+c)]^{2}+(d-d)^{2}}$

$CD = \sqrt{b^{2}+0^{2}}$

$CD = b$

Step-by-step explanation:

We defined the length of each side by the Equation of the Line Segment, which is a particular case of the Pythagorean Theorem. Let $A(x,y) = (0,0)$ , $B(x,y) = (b,0)$ , $C(x,y) = (b+c, d)$ and $D(x,y) = (c,d)$ , we construct the equations below:

Line segment AD

$AD = \sqrt{(c-0)^{2}+(d-0)^{2}}$

$AD = \sqrt{c^{2}+d^{2}}$

Line segment BC

$BC = \sqrt{[(b+c)-b]^{2}+(d-0)^{2}}$

$BC = \sqrt{c^{2}+d^{2}}$

Line segment AB

$AB = \sqrt{(b-0)^{2}+(0-0)^{2}}$

$AB = \sqrt{b^{2}+0^{2}}$

$AB = b$

Line segment CD

$CD = \sqrt{[c-(b+c)]^{2}+(d-d)^{2}}$

$CD = \sqrt{b^{2}+0^{2}}$

$CD = b$

You might be interested in

What is the integer of 160 feet above sea level

Olenka [21]

Not sure what you're asking for but the Integer of 160ft above sea level will just be +160

3 0

2 years ago

Read 2 more answers

10. Sarah is planning to fence in her backyard garden. One side of the garden is 34 feet long, another side is 30 feet long, and

KATRIN_1 [288]

Answer:

131ft is the amount of fencing material needed

Step-by-step explanation:

Perimeter is the distance around a shape: we have to sum all the distances

P = d1 + d2 + d3

P = 34 ft + 30 ft + 67 ft = 131 ft

5 0

3 years ago

Read 2 more answers

Jake bought the pizza shown above for lunch, which was cut into four equal slices. What percentage of the pizza did Jake eat if

NNADVOKAT [17]

The answer is D- 75%

6 0

2 years ago

Read 2 more answers

two functions a and b are described as follows function a: y=8x+3 function b:the rate of change is 1 and the y intercept is 4 ho

AnnZ [28]

Answer:

7

Step-by-step explanation:

rate of change of function not necessary mean linear, it can be the slope of a tangent line.

a: y=8x+3 slope = 8

b: rate of change: 1

8-1=7

I wish this is true...

3 0

2 years ago

x = c1 cos(t) + c2 sin(t) is a two-parameter family of solutions of the second-order DE x'' + x = 0. Find a solution of the seco

igomit [66]

Answer:

$x=-cos(t)+2sin(t)$

Step-by-step explanation:

The problem is very simple, since they give us the solution from the start. However I will show you how they came to that solution:

A differential equation of the form:

$a_n y^n +a_n_-_1y^{n-1}+...+a_1y'+a_oy=0$

Will have a characteristic equation of the form:

$a_n r^n +a_n_-_1r^{n-1}+...+a_1r+a_o=0$

Where solutions $r_1,r_2...,r_n$ are the roots from which the general solution can be found.

For real roots the solution is given by:

$y(t)=c_1e^{r_1t} +c_2e^{r_2t}$

For real repeated roots the solution is given by:

$y(t)=c_1e^{rt} +c_2te^{rt}$

For complex roots the solution is given by:

$y(t)=c_1e^{\lambda t} cos(\mu t)+c_2e^{\lambda t} sin(\mu t)$

Where:

$r_1_,_2=\lambda \pm \mu i$

Let's find the solution for $x''+x=0$ using the previous information:

The characteristic equation is:

$r^{2} +1=0$

So, the roots are given by:

$r_1_,_2=0\pm \sqrt{-1} =\pm i$

Therefore, the solution is:

$x(t)=c_1cos(t)+c_2sin(t)$

As you can see, is the same solution provided by the problem.

Moving on, let's find the derivative of $x(t)$ in order to find the constants $c_1$ and $c_2$ :

$x'(t)=-c_1sin(t)+c_2cos(t)$

Evaluating the initial conditions:

$x(0)=-1\\\\-1=c_1cos(0)+c_2sin(0)\\\\-1=c_1$

And

$x'(0)=2\\\\2=-c_1sin(0)+c_2cos(0)\\\\2=c_2$

Now we have found the value of the constants, the solution of the second-order IVP is:

$x=-cos(t)+2sin(t)$

3 0

3 years ago