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Alex777 [14]
3 years ago
8

Please help , ayudame Por favor

Mathematics
1 answer:
Mumz [18]3 years ago
6 0

Answer:

Line segment AD

AD = \sqrt{(c-0)^{2}+(d-0)^{2}}

AD = \sqrt{c^{2}+d^{2}}

Line segment BC

BC = \sqrt{[(b+c)-b]^{2}+(d-0)^{2}}

BC = \sqrt{c^{2}+d^{2}}

Line segment AB

AB = \sqrt{(b-0)^{2}+(0-0)^{2}}

AB = \sqrt{b^{2}+0^{2}}

AB = b

Line segment CD

CD = \sqrt{[c-(b+c)]^{2}+(d-d)^{2}}

CD = \sqrt{b^{2}+0^{2}}

CD = b

Step-by-step explanation:

We defined the length of each side by the Equation of the Line Segment, which is a particular case of the Pythagorean Theorem. Let A(x,y) = (0,0), B(x,y) = (b,0), C(x,y) = (b+c, d) and D(x,y) = (c,d), we construct the equations below:

Line segment AD

AD = \sqrt{(c-0)^{2}+(d-0)^{2}}

AD = \sqrt{c^{2}+d^{2}}

Line segment BC

BC = \sqrt{[(b+c)-b]^{2}+(d-0)^{2}}

BC = \sqrt{c^{2}+d^{2}}

Line segment AB

AB = \sqrt{(b-0)^{2}+(0-0)^{2}}

AB = \sqrt{b^{2}+0^{2}}

AB = b

Line segment CD

CD = \sqrt{[c-(b+c)]^{2}+(d-d)^{2}}

CD = \sqrt{b^{2}+0^{2}}

CD = b

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