Question

Please help , ayudame Por favor

Answer 1

Answer:

Line segment AD

$AD = \sqrt{(c-0)^{2}+(d-0)^{2}}$

$AD = \sqrt{c^{2}+d^{2}}$

Line segment BC

$BC = \sqrt{[(b+c)-b]^{2}+(d-0)^{2}}$

$BC = \sqrt{c^{2}+d^{2}}$

Line segment AB

$AB = \sqrt{(b-0)^{2}+(0-0)^{2}}$

$AB = \sqrt{b^{2}+0^{2}}$

$AB = b$

Line segment CD

$CD = \sqrt{[c-(b+c)]^{2}+(d-d)^{2}}$

$CD = \sqrt{b^{2}+0^{2}}$

$CD = b$

Step-by-step explanation:

We defined the length of each side by the Equation of the Line Segment, which is a particular case of the Pythagorean Theorem. Let $A(x,y) = (0,0)$, $B(x,y) = (b,0)$, $C(x,y) = (b+c, d)$ and $D(x,y) = (c,d)$, we construct the equations below:

Line segment AD

$AD = \sqrt{(c-0)^{2}+(d-0)^{2}}$

$AD = \sqrt{c^{2}+d^{2}}$

Line segment BC

$BC = \sqrt{[(b+c)-b]^{2}+(d-0)^{2}}$

$BC = \sqrt{c^{2}+d^{2}}$

Line segment AB

$AB = \sqrt{(b-0)^{2}+(0-0)^{2}}$

$AB = \sqrt{b^{2}+0^{2}}$

$AB = b$

Line segment CD

$CD = \sqrt{[c-(b+c)]^{2}+(d-d)^{2}}$

$CD = \sqrt{b^{2}+0^{2}}$

$CD = b$