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adell [148]
2 years ago
7

Please help with this limit, I have tried everything but this won't work. ​

Mathematics
1 answer:
Vera_Pavlovna [14]2 years ago
8 0

You're lucky that I was able to do this :)

The answer is \huge\boxed{\frac{1}{4}}

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heather has divided $6300 between two invesments, one paying 9%, the other paying 4%. If the return on her investment is $372, h
Ganezh [65]
Assuming that the two investments are  X & Y
X + Y = 6300
X = 6300 - Y                                       (1)

9/100X + 4/100 Y = 372                       (2)
replacing X from (1) into (2)
9/100(6300-Y) + 4/100 Y = 372
567 - 9/100Y +4/100Y = 372
(-9+4)/100Y = 372 - 567
5/100Y = -195
Y = 100*195/5 = 3900
From (1) we can get X
X = 6300 - 3900 = 2400

I hope this is helpful 



6 0
3 years ago
May you all help me.I need to find this answer to help me study for my midterm test.I will give Brainliest.
Slav-nsk [51]

9514 1404 393

Answer:

  • x = 17
  • y = 26

Step-by-step explanation:

In the left problem, you use the fact that <em>the sum of the segment lengths is equal to the overall length</em>.

  AC +CB = AB

  (3x -4) +(x -2) = 62

  4x -6 = 62 . . . . . collect terms

  4x = 68 . . . . . . . add 6

  x = 17 . . . . . . . . . . divide by 4

__

In the right problem, you use the fact that <em>the sum of the angles is equal to the overall angle</em>. Here, that overall angle is a linear angle, so measures 180°.

  ∠DFG +∠GFE = ∠DFE

  (5y +3) +(2y -5) = 180

  7y = 182 . . . . . . . . . . . . . . collect terms, add 2

  y = 26 . . . . . . . . . . . . . . . .divide by 7

4 0
3 years ago
ILL GIVE BRAINLIEST AND THANKS HELP
Elanso [62]

Answer:

iIm sorry dont report but i do not understand what im answering, but ill take the points thank you

7 0
3 years ago
Find the average value of the function over the given interval and all values of x in the interval for which the function equals
MrRissso [65]

The average value of f(x)=4x^3-3x^2 over [-1, 3] is

\displaystyle\frac1{3-(-1)}\int_{-1}^3(4x^3-3x^2)\,\mathrm dx=\frac14\left(x^4-x^3\right)\bigg|_{-1}^3=\frac{(3^4-3^3)-(1+1)}4=\boxed{13}

8 0
2 years ago
A EZ one<br> ......<br> (^.^) pt 4
IrinaK [193]
D, it makes the most sense
4 0
2 years ago
Read 2 more answers
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