The sum of the sequence is 750
<h3>How to determine the sum of the series?</h3>
The series is given as:
150, 120, 96, and 76.8,
Start by calculating the common ratio using:
r = T2/T1
This gives
r = 120/150
r = 0.8
The sum of the series is then calculated as:

This gives

Evaluate
S = 750
Hence, the sum of the sequence is 750
Read more about sequence at:
brainly.com/question/6561461
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Answer:
+ 9x + 8 = 0
Step-by-step explanation:
First, we have to simplify this quadratic equation:
(x+2)^2 + 5(x+2) - 6 = 0
x^2 + 4x + 4 + 5x + 10 - 6 = 0
x^2 + 9x + 8 = 0
Answer:
x = -3 and x = -3/2
Step-by-step explanation:
After writing down the polynomial, split it; put a line between 3x^2 and -18x. Look and 2x^3 + 3x^2 and -18x - 27 separately and factor them both:
p(x) = 2x^3 + 3x^2 <u>- 18x -27</u>
p(x) = x^2(2x+3) <u>-9(2x+3)</u>
Now notice how x^2 and -9 have the same factor (2x+3). That means x^2 and -9 can go together:
p(x) = (x^2 - 9)(2x+3)
Factor it once more because there's a difference of squares:
p(x) = (x+3)(x-3)(2x+3)
Now just plug in whatever makes the each bracket equal 0:
x = -3, x = 3, and x = -3/2
Those are your zeros.
Answer: y = 80*
all circles have 360* so we can subtract what we have to get what we want
360 - 110 - 90 - 80 = 80*