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2 years ago

If a relation is represented by a set of ordered pairs, explain how to determine whether the relation is a function.

Mathematics

1 answer:

yulyashka [42]2 years ago

3 0

To determine if the relation is a function, no two ordered pair must have the same abscissa or x coordinate

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Find the total amount<br> $20,700 at 9% compounded<br> semiannually for 4 years

Phantasy [73]

Answer:

41,246.046 which could be rounded to .05 cents at the end.

Step-by-step explanation:

$20700(1.09)^8$

we use this equation since we are working with interest, and we are compounding interest twice per year, for 4 years or 8 times.

hope this helps, please rate and mark as brainelst.

4 0

2 years ago

How to solve this question. I need to show my work for this question.

IrinaK [193]

Step-by-step explanation:

Recall that 1 dozen = 12 so 4 dozen cookies has a total of 48 cookies. We are going to use the following ratios to solve the problem:

$\left(\dfrac{3\:\text{eggs}}{48\:\text{cookies}}\right)$ and $\left(\dfrac{48\:\text{cookies}}{3\:\text{eggs}}\right)$

a) $12\:\text{eggs}×\left(\dfrac{48\:\text{cookies}}{3\:\text{eggs}}\right) = 192\:\text{cookies}$

b) 18 dozen cookies = 216 cookies

$216\:\text{cookies}×\left(\dfrac{3\:\text{eggs}}{48\:\text{cookies}}\right) = 13.5\:\text{eggs}$

4 0

3 years ago

A university dean is interested in determining the proportion of students who receive some sort of financial aid. Rather than ex

amm1812

Answer:

6546 students would need to be sampled.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

The dean randomly selects 200 students and finds that 118 of them are receiving financial aid.

This means that $n = 200, \pi = \frac{118}{200} = 0.59$

90% confidence level

So $\alpha = 0.1$ , z is the value of Z that has a p-value of $1 - \frac{0.1}{2} = 0.95$ , so $Z = 1.645$ .

If the dean wanted to estimate the proportion of all students receiving financial aid to within 1% with 90% reliability, how many students would need to be sampled?

n students would need to be sampled, and n is found when M = 0.01. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.01 = 1.645\sqrt{\frac{0.59*0.41}{n}}$